To answer this problem, we can find to determine angle A first by taking the arc sin of 0.83. Angle A is equal to 33.9. Hence angle B should be 90-33.9 equal to 56.10. sin of 33.9 added to the sin of 56.10 is equal to 1.38. or we can just directly add the cos values since the sin is just the same as the complementary of each
Answer:
<h2>12/36</h2>
Step-by-step explanation:
1. Find if all of the fractions are equal to the other fraction next to them.
First, let's go with the denominator of all.
6/8 = 4/3
First of all, we can easily say that this is not right, since the fact that, 6 is less than 8, and 4 is greater than 3. That's just signaling that this can't be the answer.
3/5 = 8/10
10/5=2
8/3=??? (doesn't go into 8)
So, this one is also wrong
12/16 = 36/48
48/16=3
36/12=3
<h2>
So hence, the last one or 12/16=36/48 is RIGHT.</h2>
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Answered by: FieryAnswererGT
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Answer:
BD = 8
m∠BDA = 90°
∆ABD and ∆BCD are both right triangles, each with two known side lengths.
Step-by-step explanation:
Direct answer from PLATO so change it a bit.
2W + 2L = 820
<span>LW = 42,000 or L = 42,000/W </span>
<span>substitute second equation into first equation: </span>
<span>2W + 2(42,000/W) = 820 </span>
<span>2W + 84,000/W = 820 </span>
<span>2W^2/W + 84,000/W = 820W/W </span>
<span>2W^2 - 820W + 84,000 = 0 </span>
<span>quadratic formula: </span>
<span>W = [820 +/- SQR(672,400 - 4(2)(84,000))]/2(2) </span>
<span>W = [820 +/- 20]/4 </span>
<span>W = 200, 210 </span>
<span>using second equation: </span>
<span>L = 42,000/200, 42,000/210 = 210, 200 </span>
<span>The dimensions of the parking lot are 200ft by 210ft.</span>