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dsp73
3 years ago
8

Twice a number, diminished by 17 is -3. Find the number

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
8 0

Answer:

7

Step-by-step explanation:

Let n represent the number. The problem statement tells you ...

... 2n - 17 = -3

... 2n = 14 . . . . . add 17

... n = 7 . . . . . . . divide by 2

The number is 7.

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Step-by-step explanation:

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4 0
3 years ago
Wich is bigger 0.54 or 0.6
KengaRu [80]
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8 0
4 years ago
Read 2 more answers
Find the average rate of change over the interval 7 less than or equal to X less than or equal to 10, of the function defined by
Svetradugi [14.3K]

Answer:

B. 17

Step-by-step explanation:

The average rate of change is:

m_avg = (y₂ − y₁) / (x₂ − x₁)

m_avg = (100 − 49) / (10 − 7)

m_avg = 17

7 0
4 years ago
H(x)=
UNO [17]

The average rate of change of the function over −2 ≤ x ≤ 2 is 1/2

<h3>How to determine the average rate of change?</h3>

The function is given as:

h(x) = \frac 18x^3 - x^2

The interval is given as:

−2 ≤ x ≤ 2

Calculate h(2) and h(-2)

h(2) = \frac 18 * 2^3 - (2)^2

h(2) = -3

h(-2) = \frac 18 * (-2)^3 - (-2)^2

h(-2) = -5

The average rate of change is then calculated as:

m = \frac{h(-2) - h(2)}{-2-2}

This gives

m = \frac{-5 + 3}{-4}

Evaluate

m = 1/2

Hence, the average rate of change of the function over −2 ≤ x ≤ 2 is 1/2

Read more about average rate of change at

brainly.com/question/23715190

#SPJ1

<u>Complete question</u>

h(x) = \frac 18x^3 - x^2

What is the average rate of change of h over the interval −2 ≤ x ≤ 2

7 0
2 years ago
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