All categories

3 years ago

2x+14y=-108 9x+2y= 2 Solve the following system of equations using any method

1 answer:

4 0

2x+14y=-108
63x+14y= 14 (multiply the second equation by 7 and subtract)
_____________
-61x=-122
x=-122/-61
x=2
2(2)+14y=-108
4+14y=-108
14y=-112
y=-112/14
y=-8

You might be interested in

Please help with number 16

Andre45 [30]

Answer:

2) reflexive property

3) given

4) substitution postulate

5) substitution postulate

6) addition postulate

7) partition postulate

8) equal length line segments are congruent

9) SSS theorem

Step-by-step explanation:

7 0

3 years ago

Factor completely 36a 2 - 24a + 4

stira [4]

4(9a2−6a+1)
Answer:4(3a−1)24(3a-1)2

7 0

3 years ago

What happens when you combine -3x+2x

Elan Coil [88]

-6 okokokokokokokokokokok

4 0

3 years ago

Someone please help thanks!<3

love history [14]

Answer:

y = -5x + 4/3

Step-by-step explanation:

m is the slope and b is the y intercept. m= -5 so -5 is the slope and b= 4/3 so 4/3 is the y intercept.

6 0

2 years ago

In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that

attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let X = number of soldiers killed by horse kicks in 1 year.

The random variable $X\sim Poisson(\lambda = 0.62)$ .

The probability function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...$

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

= 1 - P (X = 0) - P (X = 1)

$=1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252$

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: $\lambda=7\times0.62=4.34$

Compute the probability of no deaths in a corps over 7 years as follows:

$P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130$

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

6 0

3 years ago