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3 years ago

Where in everyday life might you need to find the percent of a whole? Give three examples.

2 answers:

6 0

Here are about 6 examples for ya honey, You have PIE, also ya have, MONEY! Because math helps you save MONEY, Ya also have, a GROCERY STORE that can help because you can count the vegetables in the store to see.

pogonyaev3 years ago

5 0

Pie, money, graphs would be three

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80% of 65 please help

Sonbull [250]

The answer is 52.

65 x 0.8 = 52.

5 0

2 years ago

Read 2 more answers

10 points help due tomarrow

strojnjashka [21]

Answer:

$\boxed{0.2}$

Step-by-step explanation:

Convert $\dfrac{12}{60}$ to a decimal

Step 1. Reduce the fraction to its lowest terms.

Divide both numerator and denominator by their greatest common factor (12)

$\dfrac{12}{60} =\dfrac{1}{5}$

Step 2. Convert the denominator to a power of 10

Multiply both numerator and denominator by 2.

$\dfrac{1}{5} \times \dfrac{2}{2} = \dfrac{2}{10}$

Step 3. Divide the numerator by the denominator

Dividing by 10 moves the decimal point one place to the left.

$\dfrac{2}{10} = \boxed{0.2}$

4 0

3 years ago

Marathon runner covered the whole distance in 4 hours running at a constant speed of 8.1 km per hour. How long would it take him

katen-ka-za [31]

Answer: it will take him 4.5 hours to cover same distance

Step-by-step explanation:

Marathon runner covered the whole distance in 4 hours running at a constant speed of 8.1 km per hour.

Speed = distance / time

Distance = speed×time

Therefore, distance covered by the marathon runner in in 4 hours, running at a speed of 8.1 km per hour is

8.1 × 4 = 32.4 kilometers

if he decreased the speed to 7.2 km per hour, the distance remains 32.4 kilometers. Therefore,

At 7.2 km per hour, the time it would take him to cover the same distance would be

Distance/ speed = 32.4/7.2 = 4.5 hours

8 0

3 years ago

A variable force of magnitude F(x) moves a body of mass m along the x-axis from x1 to x2. The net work done by the force in movi

kicyunya [14]

Answer:

$w=\frac{1}{2}m(v^2_2-v^2_1)$

Step-by-step explanation:

We are given that a variable force of magnitude F(x) moves a body along the x- axis from $x_1$ to $x_2$ .

The net work done by the force in moving the body from $x_1$ to $x_2$ .

$v_1$ =Velocity of the body at $x_1$

$v_2=$ Velocity of the body at $x_2$

We know that

Work done=Final kinetic energy-Initial kinetic energy

$w=\frac{1}{2}mv^2_2-\frac{1}{2}mv^2_1$

K.E= $\frac{1}{2}mv^2$

$Net\;work \;done=\frac{1}{2}m(v^2_2-v^2_1)$

Hence, the net work done by the force is given by

$w=\frac{1}{2}m(v^2_2-v^2_1)$

3 0

3 years ago

I need help.............

Grace [21]

$c= b - bx \\bx = b-c\\x= \frac{b-c}{b}$

7 0

3 years ago