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3 years ago

Factor completely 36a 2 - 24a + 4

1 answer:

7 0

4(9a2−6a+1)
Answer:4(3a−1)24(3a-1)2

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Joan gets $1,000 paycheck each month. She saves $50 from each paycheck. What percent of her paycheck does Joan save?

kirill [66]

Answer:

The percentage of paycheck Joan saves is 5% .

Step-by-step explanation:

Given as :

The paycheck that Joan gets each months = x = $1,000

The money that Joan saves from each paycheck = y = $50

Let The percentage of paycheck Joan saves = z%

Now, According to question

The percentage of paycheck Joan saves = $\dfrac{\textrm money that Joan saves from each paycheck}{\textrm total paycheck money}$ × 100

Or, z = $\dfrac{y}{x}$ × 100

Or, z = $\dfrac{50}{1000}$ × 100

Or, z = 5%

So, The percentage of paycheck Joan saves = z = 5%

Hence,The percentage of paycheck Joan saves is 5% . Answer

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2 years ago

Join gimkit need as many players as possible 55769

Harman [31]

Answer:

Bet

Step-by-step explanation:

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2 years ago

The ______ of a radical expression is the number indicating which root (square root, cube root, etc.) is meant.

Kobotan [32]

The correct answer is index

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2 years ago

Read 2 more answers

What is the value of x to the nearest tenth tan 64 degrees = x/7

Setler [38]

Tan64°=x/4⇒x=14.35≈14.4

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2 years ago

If 180° < α < 270°, cos⁡ α = −817, 270° < β < 360°, and sin⁡ β = −45, what is cos⁡ (α + β)?

eduard

Answer:

$cos(\alpha+\beta)=-\frac{84}{85}$

Step-by-step explanation:

we know that

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

Remember the identity

$cos^{2} (x)+sin^2(x)=1$

step 1

Find the value of $sin(\alpha)$

we have that

The angle alpha lie on the III Quadrant

The values of sine and cosine are negative

$cos(\alpha)=-\frac{8}{17}$

Find the value of sine

$cos^{2} (\alpha)+sin^2(\alpha)=1$

substitute

$(-\frac{8}{17})^{2}+sin^2(\alpha)=1$

$sin^2(\alpha)=1-\frac{64}{289}$

$sin^2(\alpha)=\frac{225}{289}$

$sin(\alpha)=-\frac{15}{17}$

step 2

Find the value of $cos(\beta)$

we have that

The angle beta lie on the IV Quadrant

The value of the cosine is positive and the value of the sine is negative

$sin(\beta)=-\frac{4}{5}$

Find the value of cosine

$cos^{2} (\beta)+sin^2(\beta)=1$

substitute

$(-\frac{4}{5})^{2}+cos^2(\beta)=1$

$cos^2(\beta)=1-\frac{16}{25}$

$cos^2(\beta)=\frac{9}{25}$

$cos(\beta)=\frac{3}{5}$

step 3

Find cos⁡ (α + β)

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

we have

$cos(\alpha)=-\frac{8}{17}$

$sin(\alpha)=-\frac{15}{17}$

$sin(\beta)=-\frac{4}{5}$

$cos(\beta)=\frac{3}{5}$

substitute

$cos(\alpha+\beta)=-\frac{8}{17}*\frac{3}{5}-(-\frac{15}{17})*(-\frac{4}{5})$

$cos(\alpha+\beta)=-\frac{24}{85}-\frac{60}{85}$

$cos(\alpha+\beta)=-\frac{84}{85}$

4 0

3 years ago