Question

DUE TMR HELP PLSSS

Answer 1

$\huge \sf \dag \: Answer :$

$\longmapsto \rm 2x + 6x + 10 = 0$

$\longmapsto \rm 8x = - 10$

$\longmapsto \sf x = - \frac{10}{8}$

Because this is just an ordinary linear equation and only has 1 value of x that meets it, it can be concluded that the value of $\tt x_1$ is equal to $\tt x_2$, then:

$\longmapsto \sf x_2 + x_2$

$\longmapsto \sf ( - \frac{10}{8} ) + ( - \frac{10}{8} )$

$\longmapsto \sf \boxed{\boxed{ \bf{ - \frac{20}{8}}} }$

-I Hope This Helps!!