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Akimi4 [234]
3 years ago
13

Identify a possible first step using the elimination method to solve the system and then find the solution to the system.

Mathematics
2 answers:
JulsSmile [24]3 years ago
6 0
The correct answer is D
EastWind [94]3 years ago
4 0

Answer:

D) multiply second equation by -6, solution (0,-2)

Step-by-step explanation:

This pair of linear equations may be solved simultaneously by using the elimination method. This will involve ensuring that the coefficient of one of the unknown variables is the same in both equations.

As such, in the given set of equations

12x – 3y = 6

2x – y = 2

We may make the coefficients of x the same by multiplying the second by 6 or the coefficient of y by multiplying the second by 3. Using the first

12x – 3y = 6

12x – 6y = 12

equation 1 - equation 2

3y = -6

y =  -2

2x + 2 = 2

x = 0

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Simplify the following expression. 4 (x-2) - 3 (x-2)​
Alex17521 [72]

Answer: x-2

Step-by-step explanation:

Given

4(x-2)-3(x-2)

Distributive property

=4x-8-3x+6

Move the like terms together

=4x-3x-8+6

combine like terms. REMEMBER you need to change signs if it is negative signs outside

=x-(8-6)

Simplify

=x-2

Hope this helps!! :)

Please let me know if you have any question.

3 0
3 years ago
Selina bought a shirt on sale and she paid 80% of the original price . The sale price of the shirt was 5$ less than the original
Tpy6a [65]
So because it was $5 off, and she paid 80% of the original price, that would mean it would have been 20% off. That means 20% = $5. Multiply that by 5 to get to 100% and you find that the shirt is $25 originally. Then you can either multiply that 20% = $5 by 4 to get 80%, or just subtract $5 from the full price. That means Selina paid $20 for the shirt.
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3 years ago
Question 8 <br> Find LM.
jok3333 [9.3K]

Answer: 11

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6 0
3 years ago
Let T:P3→P3 be the linear transformation such that T(â’2x2)=3x2+4x, T(0.5x+3)=â’3x2+3xâ’4, and T(2x2â’1)=â’3x+4. Find T(1), T(
balu736 [363]

It looks like we're told that

T(-2x^2)=3x^2+4x

T\left(\dfrac12x+3\right)=-3x^2+3x-4

T(2x^2-1)=-3x+4

We use the fact that T is linear to find T(1),T(x),T(x^2). First, we notice that

T(-2x^2)+T(2x^2-1)=T(-2x^2+2x^2-1)=T(-1)=-T(1)

We also have

T\left(\dfrac12x+3\right)=T\left(\dfrac12x\right)+T(3)=\dfrac12T(x)+3T(1)

T(2x^2-1)=T(2x^2)-T(1)=2T(x^2)-T(1)

So once we find T(1), we can determine T(x) and T(x^2). We have

T(1)=-\left(T(-2x^2)+T(2x^2-1)\right)\implies T(1)=-3x^2-x-4

and using this we find

T(x)=12x^2+12x+16

T(x^2)=-\dfrac32x^2-2x

Then

T(ax^2+bx+c)=T(ax^2)+T(bx)+T(c)=aT(x^2)+bT(x)+cT(1)

T(ax^2+bx+c)=-\dfrac32\left(a-8b+2c\right)x^2-(2a-12b+c)x+16b-4c

8 0
3 years ago
Which of the statements is true about the polygons below
uysha [10]
The answer is B, because to circumscribe a quadrilateral the sum of each two opposite angles must be 180
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4 0
3 years ago
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