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Elis [28]
3 years ago
9

At Silver Gym, membership is $30 per month, and personal training sessions are $45 each. At Fit Factor, membership is $90 per mo

nth, and personal training sessions are $35 each. In one month, how many personal training sessions would Sarah have to buy to make the total cost at the two gyms equal?
Mathematics
1 answer:
pshichka [43]3 years ago
4 0
S(x)=30x+45
F(x)=90x+35
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7L+5r=97<br><br> What’s the answer for both letters?
Kobotan [32]

Answer:

r = 11

L = 6

Step-by-step explanation:

7(6) = 42

5(11) = 55

42 + 55 = 97

8 0
3 years ago
Given the table of values, determine the base for the exponential function. x y −2 −1 0 1 1 9 2 81
IrinaK [193]

Answer:

81

Step-by-step explanation:

5 0
3 years ago
Find an angle between 0 degrees and 360 degrees that is coterminal with 950 degrees
QveST [7]

Answer:

40 degrees

Step-by-step explanation:

(to find coterminal angles to a given angle, we add 360 degrees to the given angle or subject 360 degrees from the given angle any angle any number of time).

-1400 degrees is negative angl, so to get the coterminal angle between 0 degrees and 360 degrees ( the smallest positive coterminal angle), we must add multiples of 360 degrees until we get a possitive coterminal angle:

-1400 degrees+(360 degrees*4)

=-1400 degrees+1440

=40 degrees

so the answer is 40 degrees

5 0
3 years ago
A hoop, a uniform solid cylinder, a spherical shell, and a uniform solid sphere are released from rest at the top of an incline.
Serjik [45]

Answer:

Step-by-step explanation:

Given

Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height

Suppose they have same mass and radius

time Period is given by

t=\sqrt{\frac{2h}{a}} ,where h=height of release

a=acceleration

a=\frac{g\sin \theta }{1+\frac{I}{mr^2}}

Where I=moment of inertia

a for hoop

a=\frac{g\sin \theta }{1+\frac{mr^2}{mr^2}}

a=\frac{g\sin \theta }{2}

a for Uniform solid cylinder

a=\frac{g\sin \theta }{1+\frac{mr^2}{2mr^2}}

a=\frac{2g\sin \theta }{3}

a for spherical shell

a=\frac{g\sin \theta }{1+\frac{2mr^2}{3mr^2}}

a=\frac{3g\sin \theta }{5}

a for Uniform Solid

a=\frac{g\sin \theta }{1+\frac{2mr^2}{5mr^2}}

a=\frac{5g\sin \theta }{7}

time taken will be inversely proportional to the square root of acceleration

t_1=k\sqrt{2}=1.414k

t_2=k\sqrt{\frac{3}{2}}=1.224k

t_3=k\sqrt{\frac{5}{3}}=1.2909k

t_4=k\sqrt{\frac{7}{5}}=1.183k

thus first one to reach is Solid Sphere

second is Uniform solid cylinder

third is Spherical Shell

Fourth is hoop

3 0
3 years ago
A squirrel moved 200 meters in 7,200 seconds. What was the speed of the squirrel in meters per hour? *
kati45 [8]

Answer:

100 meters per hour.

Step-by-step explanation:

7,200 seconds / 60 = 120 minutes

120 minutes / 60 = 2 hours

200 meters / 2 hours = 100 meters

Since the squirrel moved 200 meters in 2 hours, the squirrel moved 100 metres per hour.

7 0
3 years ago
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