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3 years ago

13

Solve for each equation

2 answers:

IrinaK [193]3 years ago

7 0

<span>w divided by 7 1/2
Substitute variable for numbers
5 5/6 divided by 7 1/2
Convert the mixed numbers into improper fractions
35/6 divided by 15/2
Convert the division sign to multiplication while flipping the fraction 15/2 to 2/15
35/6*2/15
Multiply
Final Answer: 70/90</span>

melisa1 [442]3 years ago

7 0

I think its b 7/9 hope this helps

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Mr. Champion invests 34,000 into a money-market fund that pays 4.8% simple interest. How long will it take for him to earn $8,16

Tanzania [10]

Answer:

5 years

Step-by-step explanation:

Step one:

Given Information

Principal= $34,000

rate = 4.8%

SImple interest = $8,160

Required

The time T of the investment

Step two:

the expression for simple interest is

$SI= PRT/100$

substitute

$8160 = 34000*4.8*T/100$

cross multiply we have

$8160*100= 34000*4.8*T\\\\816000= 163200T\\\\$

divide both sides by 163200

$816000/163200= T\\\\T= 5 years$

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3 years ago

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UNO [17]

Answer:

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Step-by-step explanation:

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2 years ago

How 152 is shown with blocks

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3 years ago

Read 2 more answers

Draw the image of the following segment after a dilation centered at the origin with a scale factor of 2/3

Irina18 [472]

Answer:

Step-by-step explanation:

Let the ends of the given segment are A and B.

Coordinates of A → (8, 6)

Coordinates of B → (12, 12)

If a point (x, y) is dilated by a scale factor 'k' about the origin, rule to be followed,

(x, y) → (kx, ky)

If k = $\frac{2}{3}$

(x, y) → $(\frac{2}{3}x, \frac{2}{3}y)$

By this rule coordinates of the image points of A and B will be,

A(8, 6) → $A'(\frac{2\times 8}{3},\frac{2\times 6}{3})$

→ A'(5.3, 4)

B(12, 12) → $B'(\frac{12\times 2}{3}, \frac{12\times 2}{3})$

→ B'(8, 8)

Now we can get the image of segment AB after dilation by a scale factor of $\frac{2}{3}$ .

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3 years ago

use the guide to construct a two column proof proving △aec≅△deb, given that ca is parallel to db and e is the midpoint of ad. gi

MrMuchimi

By using the AAA congruence property of Triangles, △aec≅△deb is proved

It is given two triangles, Δaec and Δdeb, where e is the common point known as the midpoint of ad

Also, it is given that,

ca ║db

We need to prove that, △aec≅△deb

Then we'll use AAA congruence property of Triangles to prove the situation

As ca ║db

then, ∠cae = ∠ebd (Alternate angles)

∠ace = ∠edb (Alternate angles)

and ∠aec = ∠deb (common angles)

Thus, by AAA congruence property, △aec≅△deb

Hence, proved

To learn more about, congruence property, here

brainly.com/question/2039214

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2 years ago