Answer:
y = 6x + 7.
Step-by-step explanation:
Using the point-slope form of a line
y - y1 = m(x - x1)
m = 6, x1 = 6 and y1 = 43:
y - 43 = 6(x - 6)
y - 43 = 6x - 36
y = 6x - 36 + 43
y = 6x + 7.
Answer:
Part A: 60
5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60.
12, 24, 36, 48, 60.
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Part B: 9
81 / 72 = 9
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Part C: 9 (8 + 9)
GCF of 72 and 81 is 9...
Divide 72 by 9 and get 8.
Divide 81 by 9 and get 9.
To check multiply 9 with 8, and multiply 9 by 9.
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Easy! :D (if you don't mind, may I get brainliest please?)
Answer: Loss of 3 yards
Step-by-step explanation:
The overall gain or loss of all 5 plays will be gotten by adding all the results of the plays given and this will be:
= 7 + 2 - 5 - 23 + 16
Collect like terms
= 7+2+16-5-23
= 25 - 28
= -3
The overall loss of all 5 plays will be -3 yards or loss of 3 yards
We can’t see
There is nothing attached
Answer:
a) 0.857
b) 0.571
c) 1
Step-by-step explanation:
Based on the data given, we have
- 18 juniors
- 10 seniors
- 6 female seniors
- 10-6 = 4 male seniors
- 12 junior males
- 18-12 = 6 junior female
- 6+6 = 12 female
- 4+12 = 16 male
- A total of 28 students
The probability of each union of events is obtained by summing the probabilities of the separated events and substracting the intersection. I will abbreviate female by F, junior by J, male by M, senior by S. We have
- P(J U F) = P(J) + P(F) - P(JF) = 18/28+12/28-6/28 = 24/28 = 0.857
- P(S U F) = P(S) + P(F) - P(SF) = 10/28 + 12/28 - 6/28 = 16/28 = 0.571
- P(J U S) = P(J) + P(S) - P(JS) = 18/28 + 10/28 - 0 = 1
Note that a student cant be Junior and Senior at the same time, so the probability of the combined event is 0. The probability of the union is 1 because every student is either Junior or Senior.
