You have to prove that 2 angles are conguent to the other triangles angles; example: ∠A≅∠C by the additon POC (2 of those) and then one side; example: AB≅BA by the reflexive POE (1 of those)
I cant see the triangles but thats how you do them, also im learning this right now too, look up the triangle congruence things like ASA ≅ SSS≅ HL≅ exc. a chart will explain how to prove them using that:
Answer: 10
Step-by-step explanation:
f(x)= 3 (2) - x + 6
f(x)= 6 - 2 + 6
f(x)= 4 + 6
f(x) = 10
The axis of symmetry is at x = -3.
This can be found by looking at the basic form of vertex form:
y = (x - h)^2 + k
In this basic form the vertex is (h, k). By looking at what is plugged into the equation, it is clear that h = -3 and k = -4. This means the vertex is at (-3, -4).
It is a fact that the axis of symmetry is a vertical line of x = (vertex value of x). So we can determine that the axis of symmetry is at x = -3
Answer:
the input number is -10
Step-by-step explanation:
output is always y
input is always x
so instead of y, put -52
-52=5x-2 add 2 to each side to ger 5x by itself
-50=5x divide both sides by 5 to get x by itself
-10=x
x is the input so the input is -10
