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Natali5045456 [20]
2 years ago
14

Question part points submissions used use newton's method with the specified initial approximation x1 to find x3, the third appr

oximation to the root of the given equation. (round your answer to four decimal places.) 2x3 − 3x2 + 2 = 0, x1 = −1
Mathematics
1 answer:
serious [3.7K]2 years ago
5 0

Set f(x)=2x^3-3x^2+2. Find the tangent line \ell_1(x) to f(x) at the point when x=x_1:

f'(x)=6x^2-6x\implies f'(x_1)=12 (slope of \ell_1)

\implies\ell_1(x)=12(x-x_1)+f(x_1)=12(x+1)-3=12x+9

Set x_2=-\dfrac9{12}, the root of \ell_1(x). The tangent line \ell_2(x) to f(x) at x=x_2 has slope and thus equation

f'(x_2)=\dfrac{63}8\implies\ell_2(x)=\dfrac{63}8\left(x+\dfrac9{12}\right)-\dfrac{17}{32}=7x+\dfrac{151}{32}

which has its root at x_3=-\dfrac{151}{224}\approx-0.6741.

(The actual value of this root is about -0.6777)

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White raven [17]

Answer: g(h(3)) = 59

Step-by-step explanation:

Well if its x^3 I assume it is because you wrote other coefficients before the variable.

2(3) - 2 = 6-2 = 4

So 4 is the x input for h(x)

4^3 -5 = 64-5 = 59

7 0
3 years ago
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Kryger [21]
42 x16 is this right ?
5 0
2 years ago
Stuck, need help please.
Maurinko [17]

Answer:

22.5 lbs

Step-by-step explanation:

First you find the cubic feet. That is the volume of the object which is length*width*height.

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You then take that 5/12 cubic feet and multiply it by the 54 lbs/cubic foot. The answer would be 22.5 lbs

7 0
3 years ago
Simplify 5(-2)(-11)<br><img src="https://tex.z-dn.net/?f=5%28%20-%202%29%28%20-%2011" id="TexFormula1" title="5( - 2)( - 11" alt
hram777 [196]
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3 0
2 years ago
Solve for x. 2x^2-4x=0<br> A. <br> 0, -4<br> B. <br> 0, -2<br> C. <br> 0, 2<br> D. <br> 2, 4
madam [21]

Step-by-step explanation:

2x²-4x=0

2x²=4x

2x=4

x=2

option C

7 0
2 years ago
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