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3 years ago

What is the the value of 3/0?

Mathematics

1 answer:

zavuch27 [327]3 years ago

4 0

Answer:

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hope this helps!!

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Lopez's mailing bill is automatically deducting $19 from his bank account every month. how much will the deductions total for th

suter [353]

I would say about $228 a yeah

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3 years ago

Help quick! Which BEST describes the tables?

alexdok [17]

Answer:

D. Neither table represents a function

Step-by-step explanation:

Functions require a key to go by. In this case, none of the two tables have a key from the start going down.

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3 years ago

What is the domain and range of the function f(x)=(1/5)^x

Luba_88 [7]

Answer:

domain: (- infinity, infinity) range:( 0, infinity)

Step-by-step explanation:

4 0

3 years ago

Write the limit as a definite integral on the interval [a, b], where ci is any point in the ith subinterval. Limit Interval lim

geniusboy [140]

Answer:

The corresponding definite integral may be written as

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x$

The answer of the above definite integral is

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x = 98$

Step-by-step explanation:

The given limit interval is

$\lim_{||\Delta|| \to 0} \sum\limits_{i=1}^n (4c_i + 11) \Delta x_i$

$[a, b] = [-8, 6]$

The corresponding definite integral may be written as

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x$

$\int_{-8}^6 \mathrm{(4x + 11)}\,\mathrm{d}x$

Bonus:

The definite integral may be solved as

$\int_{-8}^6 \mathrm{(4x + 11)}\,\mathrm{d}x \\\\\frac{4x^2}{2} + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\2x^2 + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\ 2(6^2 -(-8)^2 ) + 11(6 - (-8) \\\\2(36 - 64 ) + 11(6 + 8) \\\\2(-28 ) + 11(14) \\\\-56 +154 \\\\98$

Therefore, the answer to the integral is

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x = 98$

5 0

3 years ago

Find the unknown side length. Write your answer in simplest radical form.

Eva8 [605]

Answer: 1. x= 20 units, 2. x= $5\sqrt{3}$ units 3. x= $4\sqrt{2}$ units.

Step-by-step explanation:

In a right triangle,

$Hypotenuse^2= Perpendicular^2+Base^2$ (Pythagoras theorem)

1. Hypotenuse = x , Base = 16, Perpendicular = 12

$\Rightarrow\ x^2 =12^2+16^2\\\\ \Rightarrow\ x^2=144+256\\\\ \Rightarrow\ x^2=400\\\\ \Rightarrow\ x=\sqrt{400}=20$

2. Hypotenuse = 14 , Base = 11, Perpendicular = x

$\Rightarrow\ 14^2=x^2+11^2\\\\\Rightarrow\ 196=x^2+121\\\\\Rightarrow\ x^2=196-121\\\\\Rightarrow\ x^2 = 75\\\\\Rightarrow\ x=\sqrt{75}=\sqrt{25\times3}=5\sqrt{3}$

3. Hypotenuse = 9 , Base = x, Perpendicular =7

$\Rightarrow\ 9^2=x^2+7^2\\\\\Rightarrow\ 81= x^2+49\\\\\Rightarrow\ x^2=81-49\\\\\Rightarrow\ x^2=32\\\\\Rightarrow\ x=\sqrt{32}=\sqrt{16\times2}\\\\\Rightarrow\ x=4\sqrt{2}$

5 0

3 years ago