Question

The length of a new rectangular playing field is 4 yards longer than triple the width. if the perimeter of the rectangular playing field is 408 yards, what are it's dimensions?

Answer 1

The length is 4 yards longer than 3width so L = 3W+4
perimeter equal 408 yards

perimeter equal 2L +2W = 2(3W+4)+2W 

408 = 6W +8 +2W
400=8W

W = 50

L = 3*50 +4 = 154

L = 154
W = 50

P = 2L +2W
408 = 2*50 +2*154
408 = 100 +308
408 = 408

hope that this is easy understandably