The length of a new rectangular playing field is 4 yards longer than triple the width. if the perimeter of the rectangular playi
ng field is 408 yards, what are it's dimensions?
1 answer:
The length is 4 yards longer than 3width so L = 3W+4
perimeter equal 408 yards
perimeter equal 2L +2W = 2(3W+4)+2W
408 = 6W +8 +2W
400=8W
W = 50
L = 3*50 +4 = 154
L = 154
W = 50
P = 2L +2W
408 = 2*50 +2*154
408 = 100 +308
408 = 408
hope that this is easy understandably
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