Tossing a die will have 6 possible outcomes. Those are having sides that are number 1 to 6. The sample space of tossing 3 dice is equal to 6³ which is equal to 216. Now for the calculation of probabilities,
P(two 5s) = (1 x 1 x 5)/216
As we have to have the 5 in the die for two times, then for the 1 time, we can have all other numbers except 5. The answer is 5/216.
P(three 5s) = (1 x 1 x 1)/216 = 1/216
P(one 5 or two 5s) = (1 x 5 x 5)/216 + (1 x 1 x 5)/216 = 5/36
Hello there!
The would be a (right angle) because this angle is not greater than, or less than 90°.
Your correct answer would be the first option. (right angle).
Answer:54?
Step-by-step explanation:
In this case we use intersecting secant theorem
According to this theorem, GF*GE = GH*GA
So,we plug in the values
(x-3)*(x-3+9) =(x-2)*(x-2+6)
(x-3)*(x+6) =(x-2)*(x+4)
x^2 +6x -3x -18 =x^2 +4x -2x -8
x^2 +3x -18 =x^2 +2x -8
x^2 +3x -18 -x^2 -2x +8 =0
x -10 =0
x=10
So,FG =x-3 = 10-3 =7
