Answer:
$24
Step-by-step explanation:
James
Allowance per week = $6
He spends = $4
Balance = $6 - $4 = $2
Mike
Allowance per week = $7
He spends = $3
Balance = $7 - $3 = $4
Their mother's birthday is in 4 weeks
how much money can they save together in that time to buy her present?
James savings per week × 4 weeks
= $2 × 4
= $8
Mike's savings per week × 4 weeks
= $4 × 4
= $16
Total amount James and Mike can save together = $8 + $16
= $24
Answer:
The correct option is 3. The green figure is similar to the 9 by 6 figure.
Step-by-step explanation:
Let a small square represents 1 unit.
From the given figure it is noticed that
1. The dimensions of red figure is 4 by 3.
2.The dimensions of brown figure is 4 by 6.
3.The dimensions of green figure is 2 by 3.
3.The dimensions of purple figure is 3 by 6.
The dimensions of given figure is 9 by 6. The proportion of its dimensions is
The corresponding sides of two similar figure are proportional. It means the ration of sides must be .
The dimensions of green figure is 2 by 3. It means the proportion of its dimensions is .
Therefore the correct option is 3. The green figure is similar to the 9 by 6 figure.
The first one is (-2,1)
The other one is 36
Answer:
Area=6
Step-by-step explanation:
Area= lengthxwidth
- the pigpen is not a square so it could be a rectangle or any other shape with four sides.
- since the pigpen has four equal angles and it's not a square it's a rectangle.
- one side of the pigpen is three feet long--REMEMBER THAT!!!
- one foot short of 7 feet is six feet and that is the distance around the pigpen or the perimeter
Time to solve
- because the perimeter is 6 feet and one of the sides is three feet
- we divide 6 by 3 and get two which is our width
- we then multiply 2x3 to get 6
Answer:
1m 54cm
Step-by-step explanation:
10 students at 1m 40cm
15 students at 1m 58cm
13 students at 1m 60cm
Keep in mind that ratio between cm to m is 1cm/0.01m.
So let find the average by converting cm to m first for the 38 students.
10 students: 1m + (40cm)(0.01m/1cm) => 1.4 m
15 students: 1m + 58cm(0.01m/1cm) => 1.58 m
13 students: 1m 60cm(0.01m/1cm) => 1.60 m
so the average is weighted:
(10*1.4 +15*1.58 + 13(1.6))/38
Therefore the average model height is 1.54 m or 1m 54cm