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3 years ago

PLEASE I NEED HELP :(

Mathematics

1 answer:

nikdorinn [45]3 years ago

4 0

The answer should be A because for the formula of a cylinder is pi r squared x h :) I hope this helps!

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Which statements about the relationship between the two triangles below are true? Check all that apply. Triangle A C D. Angle D

Bezzdna [24]

Answer:

Triangles are similar using AAA rule of similarity.

Step-by-step explanation:

Let's take triangle ACD. Where <D =60 degrees. <A =74.9 degrees and let's find <C using angle sum property of a triangle.

Please remember the sum of interior angle of a triangle is 180 degrees.

So, m<D= 180-60-74.9 =45.1 degrees.

Other triangle RST has the two angles as 74.9 degrees and 45.1 degrees.

So, third angle <T= 180-74.9-45.1= 60 degrees.

If we see the angles of a triangle, both has same angle measures.

That's <A= <R

<C= <S

<D= <T

So, the triangles are similar using AAA rule of similarity.

5 0

2 years ago

Solve it : -<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B6%20%5Ctimes%2024%7D%20" id="TexFormula1" title=" \sqrt{6 \ti

irga5000 [103]

Answer:

Step-by-step explanation:

sqrt(6*24)

sqrt(144)

sqrt(12*12)

3 0

3 years ago

Read 2 more answers

Find the cost of flooring a square shaped room of side 10m at a rate of Rs.50 per square meter.

Ierofanga [76]

<h3>Explanation:</h3>

We have to find the area of the square shaped room.

<h3>Given:</h3>

Side of the square shaped room = 10 m

The cost of flooring a square metre is Rs. 50

The cost of flooring a square shaped room.

<h3>Formula:</h3>

Area of square = Side × Side

<h3>Solution:</h3>

Area of the square = 10 × 10 = 100 sq.m

1 sq.m = Rs. 50

100 sq.m = 50(100) = Rs. 5,000

<h2>Answer:</h2>

The cost of flooring a square shaped room of side 10 m is <u>Rs. 5,000</u><u>.</u>

6 0

3 years ago

What is the value of x?

ddd [48]

Answer:

Step-by-step explanation:

3x+x has to add up to 180

3x+x=180

4x/4=180/4

x=45

6 0

3 years ago

Read 2 more answers

Solve the following using Substitution method<br> 2x – 5y = -13<br><br> 3x + 4y = 15

Digiron [165]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Solve the following using Substitution method

2x – 5y = -13

3x + 4y = 15

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\left. \begin{array} { l } { 2 x - 5 y = - 13 } \\ { 3 x + 4 y = 15 } \end{array} \right.$

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

$2x-5y=-13, \: 3x+4y=15$

Choose one of the equations and solve it for x by isolating x on the left-hand side of the equal sign. I'm choosing the 1st equation for now.

$2x-5y=-13$

Add 5y to both sides of the equation.

$2x=5y-13$

Divide both sides by 2.

$x=\frac{1}{2}\left(5y-13\right) \\$

Multiply $\frac{1}{2}\\$ times 5y - 13.

$x=\frac{5}{2}y-\frac{13}{2} \\$

Substitute $\frac{5y-13}{2}\\$ for x in the other equation, 3x + 4y = 15.

$3\left(\frac{5}{2}y-\frac{13}{2}\right)+4y=15 \\$

Multiply 3 times $\frac{5y-13}{2}\\$ .

$\frac{15}{2}y-\frac{39}{2}+4y=15 \\$

Add $\frac{15y}{2} \\$ to 4y.

$\frac{23}{2}y-\frac{39}{2}=15 \\$

Add $\frac{39}{2}\\$ to both sides of the equation.

$\frac{23}{2}y=\frac{69}{2} \\$

Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.

$\large \underline{ \underline{ \sf \: y=3 }}$

Substitute 3 for y in $x=\frac{5}{2}y-\frac{13}{2}\\$ . Because the resulting equation contains only one variable, you can solve for x directly.

$x=\frac{5}{2}\times 3-\frac{13}{2} \\$

Multiply 5/2 times 3.

$x=\frac{15-13}{2} \\$

Add $-\frac{13}{2}\\$ to $\frac{15}{2}\\$ by finding a common denominator and adding the numerators. Then reduce the fraction to its lowest terms if possible.

$\large\underline{ \underline{ \sf \: x=1 }}$

The system is now solved. The value of x & y will be 1 & 3 respectively.

$\huge\boxed{ \boxed{\bf \: x=1, \: y=3 }}$

8 0

2 years ago