Answer:
Distance between P and R is 40.15 km.
Step-by-step explanation:
From the picture attached,
Petrol kiosk P is 12 km due North of another petrol kiosk Q.
Bearing of a police station R is 135° from P and 120° from Q.
m∠QPR = 180° - 135° = 45°
m∠PQR = 120°
m∠PRQ = 180° - (m∠QPR +m∠PQR)
= 180° - (45° + 120°)
= 180° - 165°
= 15°
Now we apply sine rule in ΔPQR to measure the distance between P and R.
PR = 
PR = 40.15 km
Therefore, distance between P and R is 40.15 km.
Rewrite so
x
is on the left side of the inequality.
12
+
8
x
−
3
x
≥
5
+
2
x
−
2
Subtract
3
x
from
8
x
.
12
+
5
x
≥
5
+
2
x
−
2
Subtract
2
from
5
.
12
+
5
x
≥
2
x
+
3
Move all terms containing
x
to the left side of the inequality.
Tap for more steps...
12
+
3
x
≥
3
Move all terms not containing
x
to the right side of the inequality.
Tap for more steps...
3
x
≥
−
9
Divide each term by
3
and simplify.
Tap for more steps...
x
≥
−
3
The result can be shown in multiple forms.
Inequality Form:
x
≥
−
3
Interval Notation:
[
−
3
,
∞
)
Say 36% of 100 is 36. so knowing half of 36 is 18, take half of 100, 50.
so 18/50 = 36
The answer is 50.
find the mean, median, and mode of the data set round to the nearest tenth 15, 1 , 4, 4, 8, 7, 15, 4, 5
Dmitriy789 [7]
<h3>Answer: mean = 7.5, median = 5, mode = 4</h3>
Answer:
See explanation
Step-by-step explanation:
Consider triangles ABC and DEC. In these triangles,
- given
- given;
as vertical angles.
So,
by SAS postulate (two sides and angle between these sides of one triangle are congruent to two sides and angle between these sides of another triangle, so triangles are congruent).
Congruent triangles have congruent corresponding parts, hence,
