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Yuliya22 [10]
3 years ago
5

match each binomial expression with the set of coefficients of the terms obtained by expanding the expression (2x+y)^4, (x+2y)^4

, (x+3y)^4, (3x+2y)^4

Mathematics
1 answer:
adell [148]3 years ago
8 0
To solve this we are going to use the fourth row of Pascal's triangle. 
First, we are going to expand our binomials:
(2x+y)^4=16x^4+32x^3y+24x^2y^2+8xy^3+y^4

(x+2y)^4=x^4+8x^3y+24x^2y^2+32xy^3+16y^4

(x+3y)^4=x^4+12x^3y+54x^2y^2+108xy^3+81y^4

(3x+2y)^4=81x^4+216x^3y+216x^2y^2+96xy^3+16y^4

We can conclude that you should match each binomial expansion <span>with the set of coefficients of the terms obtained by expanding the expression</span> as follows:
(2x+y)^4----\ \textgreater \ (16,32,24,8,1)

(x+2y)^4----\ \textgreater \ (1,8,24,32,16)

(x+3y)^4----\ \textgreater \ (1,12,54,108,81)

(3x+2y)^4----\ \textgreater \ (81,216,216,96,16)

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aev [14]
<h3>Answer: approximately 2076.56001909938 cubic cm</h3>

====================================================

Work Shown:

V1 = volume of cylinder

V2 = volume of cone on top

V3 = V1+V2 = volume of entire 3D solid figure

-----------

V1 = volume of cylinder

V1 = pi*r^2*h

V1 = pi*8.75^2*5.8

V1 = 1395.06348773471 which is approximate

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V2 = volume of cone

V2 = (1/3)*pi*r^2*h

V2 = (1/3)*pi*8.75^2*8.5

V2 = 681.49653136466  which is approximate

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V3 = V1+V2

V3 = 1395.06348773471+681.49653136466

V3 = 2076.56001909938

Answer is approximate

The units for the volume are in cubic cm.

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