Answer:
The weight of container C is 2.1kg.
Step-by-step explanation:
This question is solved using a system of equations.
I am going to say that:
x is the weight of container A.
y is the weight of container B.
z is the weight of container C.
The average weight of 3 containers A,B and C is 3.2kg.
This means that the total weight is 3*3.2 = 9.6kg. So

Container A is twice as heavy as container B.
This means that
.
Containers B is 400 g heavier than container C.
400g is 0.4kg. So
This means that
, or 
Replacing y and z as functions of x in the first equation:




Container C

The weight of container C is 2.1kg.
$ (20b + 80) is the cost to buy a frame for the panting given that measures b meters by 4 meters and charges $10 per meter for a wooden frame. This can be obtained by finding the perimeter of the painting and multiplying with the cost of wood per meter.
<h3>What is the cost of buying a frame for the painting?</h3>
Given that,
length of the painting (l) = b meters
width of the painting (b) = 4 meters
Perimeter of the painting = 2(l+b)
= 2(b+4)
= 2b + 8
Cost of the frame = (2b + 8)× $10 per meter
= $ (20b + 80)
Hence $ (20b + 80) is the cost to buy a frame for the panting given that measures b meters by 4 meters and charges $10 per meter for a wooden frame.
Learn more about finding cost of frame:
brainly.com/question/16757070
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Aluminum
It's the second element in 3A and the third in the third period.
Answer:
50 tons
Step-by-step explanation:
because you just divide 6250 by 125
First, let's assume that the numbers given corresponds to the length and width of the area.
*area = l x w*
a1 (upper area) = 8 x 2
a2 (lower area) = 6 x 2
a3 (front row) = 4 x ?
It's logical to say the a3 should have 2 as it's width. By this, we can now calculate the total length and width. For these 3 given, we can say that the total length is 18 (8 + 6 + 4) and we can get the percentage per location and we can described later how many seats it represent from the total of 138.
a1 = 8 ÷ 18 X 100
a1 = 44.44%
a2 = 6 ÷ 18 X 100
a2 = 33.33%
a3 = 4 ÷ 18 X 100
a3 = 22.22%
We now know the percentages that each area represents, so we can used these to solve for the number of seats.
a1 = 138 x 0.44
a1 = 61 seats
a2 = 138 x 0.33
a2 = 46 seats
a3 = 138 x 0.22
a3 = 31 seats
To check, we can add 61 seats + 46 seats + 31 seats, and we will get a total of 138 seats.