Cuando has simplificado la ecuación lo mas posible y las expresiones de los dos lados quedan iguales, hay soluciones infinitas. Pero, dado que lo has simplificado y son diferentes, no hay solución.
1.) 7x = 12 + 7x - 12
=> 7x = 7x => infinita solución
2.) x - 11 = 11 + x
=> x = 22 + x => no solución
3.) 2(4x - 6) = 8(x + 2)
=> 8x - 12 = 8x + 16 => 8x = 8x + 28 => no solución
4.) 2x - 9 = 2x - 9
=> infinita solución
5.) 8 + 4x = 4x + 10
=> 4x = 4x - 2 => no solución
Answer: 11:15 AM
Step-by-step explanation:
9:00 plus an hour and 15 minutes (75 minutes) makes it 10:15. Then bake for an hour (60 minutes), makes it 11:15
Answer:
y = - 9
Step-by-step explanation:
Substitute in -1 for x
8(-1) - 2y = 10
-8 - 2y = 10
Subtract -8 from both sides
-8 - (-8) cancels out to 0
10 - (-8) = 18
We are left with:
-2y = 18
Divide by -2 on both sides.
-2y/-2 = y
18/-2 = -9
y = -9
Answer: The value of k for which one root of the quadratic equation kx2 - 14x + 8 = 0 is six times the other is k = 3.
Let's look into the solution step by step.
Explanation:
Given: A quadratic equation, kx2 - 14x + 8 = 0
Let the two zeros of the equation be α and β.
According to the given question, if one of the roots is α the other root will be 6α.
Thus, β = 6α
Hence, the two zeros are α and 6α.
We know that for a given quadratic equation ax2 + bx + c = 0
The sum of the zeros is expressed as,
α + β = - b / a
The product of the zeros is expressed as,
αβ = c / a
For the given quadratic equation kx2 - 14x + 8 = 0,
a = k, b = -14, c = 8
The sum of the zeros is:
α + 6α = 14 / k [Since the two zeros are α and 6α]
⇒ 7α = 14 / k
⇒ α = 2 / k --------------- (1)
The product of the zeros is:
⇒ α × 6α = 8 / k [Since the two zeros are α and 6α]
⇒ 6α 2 = 8 / k
⇒ 6 (2 / k)2 = 8 / k [From (1)]
⇒ 6 × (4 / k) = 8
⇒ k = 24 / 8
⇒ k = 3
