Factoring a quadratic in the equation z^2-7z+10=0 what are the a b and c values (pick it blurry but I wrote what it say need ans
2 answers:
Answer:
a=1 b = -7 and c = 10
Step-by-step explanation:
z^2-7z+10=0
The quadratic is written in the form
ax^2 +bx+c=0
Letting x become z
az^2 + bz+c =0
a=1 b = -7 and c = 10
Answer:
a = 1, b = -7, c = 10
Step-by-step explanation:
Az² + Bz + C is the general form of a quadratic
Where,
A is the coefficient of z²
B is the coefficient of z
C is the constant
z² -7z + 10=0
a = 1, b = -7, c = 10
In case you need the factorized form too:
z² - 7z + 10 = 0
z² - 5z - 2z + 10 = 0
z(z - 5) -2(z - 5) = 0
(z - 2)(z - 5) = 0
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Step-by-step explanation:
Answer =-0.7x +0 Find the gradient by y2-y1/x2-x1 -14 -7/ 20- -10 -21/30 -0.7 And plug in the coordinates to find the y intercept 7= -0.7 (-10) + c C=0
ok so u need to find the gcd and then subtract.
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Step-by-step explanation:
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