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3 years ago

11

Please help me I am stuck on this question.

1 answer:

ladessa [460]3 years ago

3 0

I think it is 6 I hope you get it right good luck but I think that is the answer but it should be 6

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What is 4/8 + 2/8 = ?

Deffense [45]

Answer:

4/8 =1/2

2/8 = 1/4

1/2+1/4, we take Lcm,

2+4/2 =6/4

3/2

7 0

3 years ago

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What is the median of the following numbers

den301095 [7]

Answer: You did not give me any numbers...

Step-by-step explanation:

just to say, The median is the value separating the higher half of a data sample, a population, or a probability distribution, from the lower half. In simple terms, it may be thought of as the "middle" value of a data set.

3 0

3 years ago

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A piece of paper is to display ~128~ 128 space, 128, space square inches of text. If there are to be one-inch margins on both si

Grace [21]

Answer:

The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

Step-by-step explanation:

We have that:

$Area = 128$

Let the dimension of the paper be x and y;

Such that:

$Length = x$

$Width = y$

So:

$Area = x * y$

Substitute 128 for Area

$128 = x * y$

Make x the subject

$x = \frac{128}{y}$

When 1 inch margin is at top and bottom

The length becomes:

$Length = x + 1 + 1$

$Length = x + 2$

When 2 inch margin is at both sides

The width becomes:

$Width = y + 2 + 2$

$Width = y + 4$

The New Area (A) is then calculated as:

$A = (x + 2) * (y + 4)$

Substitute $\frac{128}{y}$ for x

$A = (\frac{128}{y} + 2) * (y + 4)$

Open Brackets

$A = 128 + \frac{512}{y} + 2y + 8$

Collect Like Terms

$A = \frac{512}{y} + 2y + 8+128$

$A = \frac{512}{y} + 2y + 136$

$A= 512y^{-1} + 2y + 136$

To calculate the smallest possible value of y, we have to apply calculus.

Different A with respect to y

$A' = -512y^{-2} + 2$

Set

$A' = 0$

This gives:

$0 = -512y^{-2} + 2$

Collect Like Terms

$512y^{-2} = 2$

Multiply through by $y^2$

$y^2 * 512y^{-2} = 2 * y^2$

$512 = 2y^2$

Divide through by 2

$256=y^2$

Take square roots of both sides

$\sqrt{256=y^2$

$16=y$

$y = 16$

Recall that:

$x = \frac{128}{y}$

$x = \frac{128}{16}$

$x = 8$

Recall that the new dimensions are:

$Length = x + 2$

$Width = y + 4$

So:

$Length = 8 + 2$

$Length = 10$

$Width = 16 + 4$

$Width = 20$

To double-check;

Differentiate A'

$A' = -512y^{-2} + 2$

$A" = -2 * -512y^{-3}$

$A" = 1024y^{-3}$

$A" = \frac{1024}{y^3}$

The above value is:

$A" = \frac{1024}{y^3} > 0$

This means that the calculated values are at minimum.

<em>Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches</em>

3 0

3 years ago

Least to greatest;]

alexandr1967 [171]

Answer:

Least to greatest is: 0.0625, 6.75% and $\frac{7}{10}$ .

Step-by-step explanation:

Given:

The three quantities to compare are:

6.75%, 0.0625, and $\frac{7}{10}$

Let us convert each into percentage.

6.75% is already in percentage.

We multiply a number by 100 to convert it to percentage form.

So, $0.0625\times 100=6.25\%$

$\frac{7}{10}\times 100=\frac{700}{10}=70\%$

Now, on comparing all the three percentage, we conclude that,

70% is the greatest and 6.25% is the least.

So, order from least to greatest is:

$6.25\%$

5 0

3 years ago

Which of the following rules should be use to find the area of a triangle?

lbvjy [14]

The area of a triangle is half the product of the base and the height.

Since multiplication is commutative, the following expressions are equivalent:

$A=(bh)\cdot \dfrac{1}{2} = \dfrac{b}{2}\cdot h = \dfrac{h}{2}\cdot b$

So, option D is correct

4 0

3 years ago