From the given function modeling the height of the ball:
f(x)=-0.2x^2+1.4x+7
A] The maximum height of the ball will be given by:
At max height f'(x)=0
from f(x),
f'(x)=-0.4x+1.4
solving for x we get:
-0.4x=-1.4
x=3.5ft
thus the maximum height would be:
f(3.5)=-0.2(3.5)^2+1.4(3.5)+7
f(3.5)=9.45 ft
b]
How far from where the ball was thrown did this occur:
from (a), we see that at maximum height f'(x)=0
f'(x)=-0.4x+1.4
solving for x we get:
-0.4x=-1.4
x=3.5ft
This implies that it occurred 3.5 ft from where the ball was thrown.
c] How far does the ball travel horizontally?
f(x)=-0.2x^2+1.4x+7
evaluationg the expression when f(x)=0 we get:
0=-0.2x^2+1.4x+7
Using quadratic equation formula:
x=-3.37386 or x=10.3739
We leave out the negative and take the positive answer. Hence the answer 10.3739 ft horizontally.
Answer:
x+5y+5=0
Step-by-step explanation:
y=5x+6
Therefore the gradient of the line = 5
Now reciprocate the gradient and negate it
i.e -1/5
let (x,y) and (-15,2) be points on the line
y-2/x-(-15)=-⅕
5y-10=-x-15
5y-10+15+x=0
x+5y+5=0
Therefore the equation of the line =
x+5y+5=0
I don't know if this is right but i think the answer is 11 because as the number of people in the group goes up the price keeps decreasing by 3 so I made a table to see the difference...
1=42
8=39
9=36
10=33
11=30
