Answer:m∠1 = 145°
m∠2 = 35°
m∠3 = 35°
m∠4 = 145°
m∠5 = 145°
m∠6 = 35°
m∠7 = 35°
m∠8 = 145°
Step-by-step explanation:
Answer:
1) At least 6.
2) $2194.8
3) $2326.49
4) 38 mph on average.
Step-by-step explanation:
Comment if you do need the steps
Answer:
It's asking you to find the inputs of the function.
Step-by-step explanation:
Basically, when you input something, you replace "x" in the equation with the number you want to input. For example, if I had the equation: 5x/6+5, then I wanted to input "5", then 5 would replace x in the equation, making 5(5)/6+5. The output they are giving you is simply evaluating the equation that you used to input x, so basically in the case I gave you, the output would be 5(5)/6+5, or 25/6+5, and 55/6. Using the outputs, they want you to find the inputs.
We could put the domain into the x values to get the y values (range).
y = 3(-3) - 4
y = -9 - 4
y = -13
y = 3(-1) - 4
y = -3 - 4
y = -7
y = 3(4) - 4
y = 12 - 4
y = 8
Answer:
80,00![ft^{2}](https://tex.z-dn.net/?f=ft%5E%7B2%7D)
Step-by-step explanation:
According to my research, the formula for the Area of a rectangle is the following,
![A = L*W](https://tex.z-dn.net/?f=A%20%3D%20L%2AW)
Where
- A is the Area
- L is the length
- W is the width
Since the building wall is acting as one side length of the rectangle. We are left with 1 length and 2 width sides. To maximize the Area of the parking lot we will need to equally divide the 800 ft of fencing between the <u>Length and Width.</u>
800 / 2 = 400ft
So We have 400 ft for the length and 400 ft for the width. Since the width has 2 sides we need to divide 60 by 2.
400/2 = 200 ft
Now we can calculate the maximum Area using the values above.
![A = 400ft*200ft](https://tex.z-dn.net/?f=A%20%3D%20400ft%2A200ft)
![A = 80,000ft^{2}](https://tex.z-dn.net/?f=A%20%3D%2080%2C000ft%5E%7B2%7D)
So the Maximum area we are able to create with 800 ft of fencing is 80,00![ft^{2}](https://tex.z-dn.net/?f=ft%5E%7B2%7D)
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