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gtnhenbr [62]
3 years ago
9

Which of these values for p and a will cause the function f(x)=Pa^x to be an exponential growth function?

Mathematics
2 answers:
Lera25 [3.4K]3 years ago
8 0
Grouth is when a>1
if a=1, theer is no change
if a<1, it is exponetial decay


B is answer
finlep [7]3 years ago
4 0

The <em><u>correct answer</u></em> is:

B.P=1/4;a=5  

Explanation:

In order to represent exponential growth, a must be a positive number larger than 1.  If it is a fraction less than 1, we are basically taking a percent (less than 100) of the number; this makes it smaller, which would be decay.  If a is a negative, the values would alternate between positive and negative.

The only option where a is a positive number larger than 1 is P=1/4 and a=5.

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When the value of the y-intercept(b) change by subtracting a number from "b" in the equation "y=mx+b", the graph will move of sh
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True. The graph will shift down if we subtract a number from "b"

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"b" represents the y-intercept, or how high up on the y axis the graph intersects.

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3 years ago
According to the National Association of Colleges and Employers, the average starting salary for new college graduates in health
katen-ka-za [31]

Answer:

a) The probability that a new college graduate in business will earn a starting salary of at least $65,000 is P=0.22965 or 23%.

b) The probability that a new college graduate in health sciences will earn a starting salary of at least $65,000 is P=0.11123 or 11%.

c) The probability that a new college graduate in health sciences will earn a starting salary of less than $40,000 is P=0.14686 or 15%.

d) A new college graduate in business have to earn at least $77,133 in order to have a starting salary higher than 99% of all starting salaries of new college graduates in the health sciences.

Step-by-step explanation:

<em>a. What is the probability that a new college graduate in business will earn a starting salary of at least $65,000?</em>

For college graduates in business, the salary distributes normally with mean salary of $53,901 and standard deviation of $15,000.

To calculate the probability of earning at least $65,000, we can calculate the z-value:

z=\frac{x-\mu}{\sigma} =\frac{65000-53901}{15000} =0.74

The probability is then

P(X>65,000)=P(z>0.74)=0.22965

The probability that a new college graduate in business will earn a starting salary of at least $65,000 is P=0.22965 or 23%.

<em>b. What is the probability that a new college graduate in health sciences will earn a starting salary of at least $65,000?</em>

<em />

For college graduates in health sciences, the salary distributes normally with mean salary of $51,541 and standard deviation of $11,000.

To calculate the probability of earning at least $65,000, we can calculate the z-value:

z=\frac{x-\mu}{\sigma} =\frac{65000-51541}{11000} =1.22

The probability is then

P(X>65,000)=P(z>1.22)=0.11123

The probability that a new college graduate in health sciences will earn a starting salary of at least $65,000 is P=0.11123 or 11%.

<em>c. What is the probability that a new college graduate in health sciences will earn a starting salary less than $40,000?</em>

To calculate the probability of earning less than $40,000, we can calculate the z-value:

z=\frac{x-\mu}{\sigma} =\frac{40000-51541}{11000} =-1.05

The probability is then

P(X

The probability that a new college graduate in health sciences will earn a starting salary of less than $40,000 is P=0.14686 or 15%.

<em />

<em>d. How much would a new college graduate in business have to earn in order to have a starting salary higher than 99% of all starting salaries of new college graduates in the health sciences?</em>

The z-value for the 1% higher salaries (P>0.99) is z=2.3265.

The cut-off salary for this z-value can be calculated as:

X=\mu+z*\sigma=51,541+2.3265*11,000=51,541+25,592=77,133

A new college graduate in business have to earn at least $77,133 in order to have a starting salary higher than 99% of all starting salaries of new college graduates in the health sciences.

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Are you trying write it into slope intercept form ?
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