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gtnhenbr [62]
3 years ago
9

Which of these values for p and a will cause the function f(x)=Pa^x to be an exponential growth function?

Mathematics
2 answers:
Lera25 [3.4K]3 years ago
8 0
Grouth is when a>1
if a=1, theer is no change
if a<1, it is exponetial decay


B is answer
finlep [7]3 years ago
4 0

The <em><u>correct answer</u></em> is:

B.P=1/4;a=5  

Explanation:

In order to represent exponential growth, a must be a positive number larger than 1.  If it is a fraction less than 1, we are basically taking a percent (less than 100) of the number; this makes it smaller, which would be decay.  If a is a negative, the values would alternate between positive and negative.

The only option where a is a positive number larger than 1 is P=1/4 and a=5.

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The answer is most likely -1 31/33

I have a hard time with fractions so I usually just go into my calculator and change it to a decimal. For example with -5 1/3 I would insert 1/3 into my calculator to change it to a decimal and then simply tack on the -5 to it. So in decimal form 1/3 is 0.333... so with the -5 added on its -5.333... Do the same for the other number and then divide. You will get -1.9393... all you have to do is go into your calculator and try out 11/12 or 31/33 to see which equals 0.9393... because those are the only options with a -1. In this case 31/33 equals 0.9393 s -1 31/33 is the answer

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From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s
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<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

  • The lower limit is 0.5.
  • The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of \frac{1+\alpha}{2}.

60 out of 100 scores are passing scores, hence n = 100, \pi = \frac{60}{100} = 0.6

95% confidence level

So \alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

  • The lower limit is 0.5.
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A similar problem is given at brainly.com/question/16807970

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