I think it might be point be but I’m not sure if it’s correct I’m sorry if it’s wrong
Answer:
(i) (f - g)(x) = x² + 2·x + 1
(ii) (f + g)(x) = x² + 4·x + 3
(iii) (f·g)(x) = x³ + 4·x² + 5·x + 2
Step-by-step explanation:
The given functions are;
f(x) = x² + 3·x + 2
g(x) = x + 1
(i) (f - g)(x) = f(x) - g(x)
∴ (f - g)(x) = x² + 3·x + 2 - (x + 1) = x² + 3·x + 2 - x - 1 = x² + 2·x + 1
(f - g)(x) = x² + 2·x + 1
(ii) (f + g)(x) = f(x) + g(x)
∴ (f + g)(x) = x² + 3·x + 2 + (x + 1) = x² + 3·x + 2 + x + 1 = x² + 4·x + 3
(f + g)(x) = x² + 4·x + 3
(iii) (f·g)(x) = f(x) × g(x)
∴ (f·g)(x) = (x² + 3·x + 2) × (x + 1) = x³ + 3·x² + 2·x + x² + 3·x + 2 = x³ + 4·x² + 5·x + 2
(f·g)(x) = x³ + 4·x² + 5·x + 2
Answer:
it is not a solution
Step-by-step explanation:
You would plug them in
-1=3(2)-2
-1=6-2
-1=4
Answer:
Number of volleyballs bought = 8
Number of basketballs bought = 11
Step-by-step explanation:
Given that:
Total amount spent = $204.20
Let,
x be the number of volleyballs
y be the number of basketballs
According to given statement;
y = x+3 Eqn 1
8.20x+12.60y=204.20 Eqn 2
Putting value of y from Eqn 1 in Eqn 2
8.20x + 12.60(x+3) = 204.20
8.20x + 12.60x + 37.80 = 204.20
20.80x = 204.20 - 37.80
20.80x = 166.40
Dividing both sides by 20.80
Putting x=8 in Eqn 1
y = 8+3 = 11
Hence,
Number of volleyballs bought = 8
Number of basketballs bought = 11
2*1*1= 2 m^3 per chest
2 m^3 per chest* 18 chests= 36 m^3 total
Final answer: 36 m^3
