Even though it has not happened yet again
648 is the three-digit positive integers have three different digits
According to the statement
we have given that there are three positive digit number are formed with three distinct digits.
And we have to find that the how many words are formed with distinct numbers.
So, to solve this type of problem the Combination formula is best.
Because it provides the all possibilities that from how many ways numbers are formed.
So, from a combination formula
here we take 9 two times because first time when we let a number then remaining numbers are 9. and second time remaining numbers are also 9 because we let the distinct number but for third number there will be a probability that choosing number will be same.
So, Three digit positive number become from 9*9*8 =648
So, 648 is the three-digit positive integers have three different digits.
Learn more about COMBINATION here brainly.com/question/4658834
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Step-by-step explanation:
these are multiplications.
you could also write
4 + 5×(p - 1)
now, we need to calculate the contents of brackets (if we can), then do the multiplications and divisions, before we can do the then remaining additions and subtractions.
if we cannot do a calculation directly (because there is a variable involved), we need to do and document the single steps for the individual parts involved.
so,
4 + 5×(p - 1) = 4 + 5×p + 5×-1 = 4 + 5p - 5 = 5p - 1
remember, a multiplication of 2 expressions is done by multiplying every term of one expression with every term of the other expression and adding the results up (by considering their individual signs, of course).
Answer:
x=4
Step-by-step explanation:
Step 1: Cross-multiply
Step 2: Divide both sides by 15
Hope it helps:)
