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3 years ago

Graph the equations to find the solution(s) to the system.

Mathematics

1 answer:

Scilla [17]3 years ago

6 0

Check the picture below.

recall that a solution is where both graphs meet.

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Let f(x)=3x-7 and g(x)=2x². Perform the function operation and then find the domain of the result.

olya-2409 [2.1K]

Answer: A

Step-by-step explanation:

$f(x)=3x-7\\g(x)=2x^2$

$(f-g)(x)=3x-7-(2x^2)\\(f-g)(x)=3x-7-2x^2\\(f-g)(x)=-2x^2+3x-7$

6 0

2 years ago

CASSANDRA WORKS AS CLERK AT A DEPARTMENT STORE ,SHE EARNS 1 375.00 A WEEK.SHE SAVE 25% OF THIS FOR HER SAVINGS.HOW MUCH DOES SHE

defon

the man

Step-by-step explanation:

6 0

2 years ago

To practice for a competition, Carly swam 0.51 kilometer in the pool each day for 3 weeks. How many meters did Carly swim in tho

erica [24]

Answer:

0.51km × 1000 = 510m

510m × (3×7) = 510m × 21 = 10710m in whole

Step-by-step explanation:

first we transform km to m (multiply by 1000)

then we count how much days are in three weeks ( 3 weeks × 7 days)

then we just multiply the meters per day × the days

99% it's true

7 0

3 years ago

Write an exponential function for the graph that passes through the points (0,4) and (2, 36). Use the formula y=ab^x

fomenos

Answer:

Using the equation y = abx , substitute both of your given points into that equation.

2 = ab2 and 4 = ab3 Solve each equation for a.

2⁄b2 and 4⁄b3 = a Therefore, 2⁄b2 = 4⁄b3

Cross multiply: 2b3 = 4b2 Divide both sides by b2

2b = 4 a = 2/4 = 1/2

b = 2

y = 1 (2)x

Step-by-step explanation:

3 0

3 years ago

Consider the probabilities of people taking pregnancy tests. Assume that the true probability of pregnancy for all people who ta

Valentin [98]

Using conditional probability, it is found that there is a 0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

<h3>What is Conditional Probability?</h3>

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this problem, the events are:

Event A: Positive test result.

Event B: Pregnant.

The probability of a positive test result is composed by:

99% of 10%(truly pregnant).

2% of 90%(not pregnant).

Hence:

$P(A) = 0.99(0.1) + 0.02(0.9) = 0.117$

The probability of both a positive test result and pregnancy is:

$P(A \cap B) = 0.99(0.1)$

Hence, the conditional probability is:

$P(B|A) = \frac{0.99(0.1)}{0.117} = 0.8462$

0.8462 = 84.62% probability that a woman who gets a positive test result is truly pregnant.

You can learn more about conditional probability at brainly.com/question/14398287

7 0

2 years ago