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elena55 [62]
3 years ago
11

3. Assume a disk drive from the late 1990s is configured as follows. The total storage is approximately 675MB divided among 15 s

urfaces. Each surface has 612 tracks; there are 144 sectors/track, 512 bytes/sector, and 8 sectors/cluster. The disk turns at 3600 rpm. The tract-to-track seek time is 20ms, and the average seek time is 80ms. Now assume that there is a 360KB file on the disk. On average, how long does it take to read all of the data in the file? Assume that the first track of the file is randomly placed on the disk, that the entire file lies on adjacent tracks, and that the file completely fills each track on which it is found. A seek must be performed each time the I/O head moves to a new track. Show your calculations
Computers and Technology
1 answer:
oksano4ka [1.4K]3 years ago
3 0

Answer:

total time to read whole file = ( 81.380208 mili seconds ) + 80ms + 80ms

Explanation:

Size of a surface = 675/15 = 45 MB

Size of a track = (Number of sectors per track)*(Size of a sector)

= (144*512)Bytes

= 73.728 KB

Number of tracks where 360KB file is located = 360/73.728 = 4.8828125 (Approx 5 tracks)

So Seek time to go the first track of the file = 80 ms

And after seek time for track to track movement = 4*20 = 80 ms

We need 4.8828125 rotations to read whole file.

Time for 4.8828125 ratations = (60.0/3600.0)*4.8828125 seconds = 0.081380208 seconds = 81.380208 mili seconds

So total time to read whole file = ( 81.380208 mili seconds ) + 80ms + 80ms

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Following are the program, which can be below:

import java.util.*; //defining header file

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public static void main(String[] arc) //defining main method

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int total_number=0,max_val=0,min_val=0,neg_val=0,pos_val=0,neg_count=0,pos_count=0,x; //defining variables

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else  //defining else block

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max_val = x; //assign maximum value

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min_val = x; //assign minimum value

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if(x > 0) //input values  

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pos_count++; //count positive value

pos_val+=x; // add positive values

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neg_count++;//count negative value

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System.out.println("positive value average= "+(pos_val/(double)pos_count));

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System.out.println("no positive values found");

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}

Output:

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8

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negative values Average= -13.5

all values average= 4.0

maximum value = 22

minimum value = -22

Explanation:

The Description of the above java program can be described as follows:

  • In the above code first we import the package for user input, then defines the variable "total_number,max_val,min_val,neg_val,pos_val,neg_count, pos_count,x" to store the value prints its value.
  • In the next step, a scanner class object is created for user input and defines a while loop, that checks input value isn't equal to 0, inside the loop a conditional statement defines that cont and calculates all positive, negative, and all values addition.
  • At the another conditional statement is defines, that prints all value average, and also prints maximum, minimum value.
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