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Lorico [155]
2 years ago
11

Como podemos calcular a média dos valores da Tabela acima no Excel? Assinale a alternativa correta

Computers and Technology
1 answer:
AVprozaik [17]2 years ago
5 0
Correta média (A1:A3) A RESPOSTA CORRETA É =Meia (A1:A3)
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What does it mean to prioritize tasks?
salantis [7]

Answer:

to rank tasks from most to least important

Explanation:

Prioritize means to choose priority, obviously and priority is the thing is the thing which, among other things, have the biggest importance.

Every day, especially in business, one finds himself swimming in tasks up to his neck. Obviously, not all of them can be successfully finished, or at least not without sacrificing one's personal life or sleep.

Prioritizing, therefore, serves as a helpful organising tool. After writing down all tasks that need to be done, a person should rank them by priority, which means that only urgent and important tasks will be dealt with immediately. Tasks of lower priority will be postponed, delegated or simply deleted.

6 0
2 years ago
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1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0
3 years ago
There is a development team delivering a new software package with agile and devops frameworks. in one of the releases, the auto
Olin [163]

A practice that should be implemented in the aforementioned situation is to separate the Agile and DevOps software development framework.

<h3>What is a unit test?</h3>

A unit test can be defined as an automated test that's typically written and run by a software developer, so as to ensure that a section (component) of a software application meets its design specifications, functionalities and requirements.

In this scenario, a practice that should be implemented by the software developer is to separate the Agile and DevOps software development framework.

Read more on unit test here: brainly.com/question/22900395

#SPJ1

4 0
2 years ago
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Will somebody help me???? ANYBODY?? PLZZZZZZZZZZZZ
romanna [79]
I've never seen that third syntax. If it's legit, it probably does the same as I and II, which are the same.
6 0
3 years ago
"running computer programs and their data are stored in ___"
Lesechka [4]

Solution:

Running computer programs and their data are stored in Rom.

ROM is "built-in" computer memory containing data that normally can only be read, not written to. ROM contains the programming that allows your computer to be "booted up" or regenerated each time you turn it on. Unlike a computer's random access memory (RAM), the data in ROM is not lost when the computer power is turned off. The ROM is sustained by a small long-life battery in your computer.

5 0
3 years ago
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