9514 1404 393
Answer:
5/9 m/min
Step-by-step explanation:
The depth of the water is 2/5 of the depth of the trough, so the width of the surface will be 2/5 of the width of the trough:
2/5 × 2 m = 4/5 m
Then the surface area of the water is ...
A = LW = (18 m)(4/5 m) = 14.4 m²
The rate of change of height multiplied by the area gives the rate of change of volume:
8 m³/min = (14.4 m²)(h')
h' = (8 m³/min)/(14.4 m²) = 5/9 m/min
May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x
1) If h(x) = 5x and k(x) = 1/x
Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)
2) If h(x) = 5 + x and k (x) = 1/x
Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]
Answer:
p=122 q=80 r=80
Step-by-step explanation:
The two cars lying on one side of the plane are 50 meters apart.
<h3>What is an equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
let us assume that the height is 100 m. Let d represent the horizontal distance. For depression of 38°, Ф = 90 - 38 = 52°, hence:
tan(52°) = d / 100
d = 128 m
For depression of 52°, Ф = 90 - 52 = 38°, hence:
tan(38°) = d / 100
d = 78 m
Distance apart = 128 - 78 = 50 m.
The two cars lying on one side of the plane are 50 meters apart.
Find out more on equation at: brainly.com/question/2972832
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