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Deffense [45]
3 years ago
13

Linda left home and drove for 2 hours. She stopped for lunch then drove for another 3 hours at a rate that is 10 mph higher than

the rate before she had lunch. If the total distance Linda traveled is 250 miles, what was the rate before lunch
Mathematics
1 answer:
Verdich [7]3 years ago
6 0

Answer:

44 mph

Step-by-step explanation:

Given that:

Before lunch :

Time taken = 2hrs ; at speed = x mph

After lunch :

Time taken = 3hrs ; at speed = x + 10 mph

Total distance covered = 250 miles :

Distance = speed * time

(2 * x) + (3 * (x + 10)) = 250

2x + 3x + 30 = 250

5x + 30 = 250

5x = 250 - 30

5x = 220

x = 220/ 5

x = 44 mph

Rate before lunch is 44mph

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You flip a coin and then roll a 6-sided number cube (a die).
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Answer:

a)  No, it does not matter whether you roll the die or flip the coin first, as these two events are <u>independent</u> of each other, which means they do not affect each other.

b) Yes.

  • Let event 1 be flipping a coin and event 2 be rolling a die.
  • Let event 1 be rolling a die and event 2 be flipping a coin.

The likelihood that any outcome will occur will not change, as the events are independent.

c) see attached

d)   12 outcomes  (H = head, T = tail, numbers represent the value of the die)

H 1           T 1

H 2          T 2

H 3          T 3

H 4          T 4

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H 6          T 6

e)  

\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}

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