Linda left home and drove for 2 hours. She stopped for lunch then drove for another 3 hours at a rate that is 10 mph higher than
the rate before she had lunch. If the total distance Linda traveled is 250 miles, what was the rate before lunch
1 answer:
Answer:
44 mph
Step-by-step explanation:
Given that:
Before lunch :
Time taken = 2hrs ; at speed = x mph
After lunch :
Time taken = 3hrs ; at speed = x + 10 mph
Total distance covered = 250 miles :
Distance = speed * time
(2 * x) + (3 * (x + 10)) = 250
2x + 3x + 30 = 250
5x + 30 = 250
5x = 250 - 30
5x = 220
x = 220/ 5
x = 44 mph
Rate before lunch is 44mph
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