Answer:
A = 0.8 litres
B = 0.7 litres
C = 0.5 litres
D = 0.2 litres
Step-by-step explanation
Here's what we know:
1. Jug A = B + .1 litres
2. Jug C = B - 200 (or 0.2 litres)
3. Jug D = .25 x A
4. Jug A + Jug B = 1.5 litres
In problem 1, we learned that Jug A has .1 litres more than Jug B and in problem 4, the two of them added together are 1.5 litres. To solve this we can combine the problems.
B + .1 litres + B = 1.5 litres
2B + .1 = 1.5
Subtract .01 from each side and you have 2B = 1.4
Divide each side by 2 and you have B = 0.7 litres
Plug this info into problem 1 and you can solve for A. (0.7 + 0.1 = 0.8)
Plug this info into problem 2 and you can solve for C. (0.7 - 0.2 = 0.5)
Since you have A, you can use that info to solve problem 3 (0.25 x 0.8 = 0.2)
Answer:
10
Step-by-step explanation:
10
Answer:
x=47
Step-by-step explanation:
We can use the triangle bisector theorem
TK TV
----------- = -----------
YK YV
Substituting what we know
87.5 77
----------- = -----------
x-22 22
Using cross products
87.5 * 22 = 77 *(x-22)
Distribute
1925 =77x - 1694
Add 1694 to each side
1925 + 1694 =77x - 1694+1694
3619 = 77x
Divide by 77
3619/77 = 77x/77
47=x
Answer:
9x square + y squared + z squared
Step-by-step explanation:
Multiply all the numbers by '-'. Then square them all
Answer:
I am pretty sure the answer is 324 or 300