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2 years ago

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A Flagpole casts a shadow 32 feet long. If a man is 6 feet tall casts a shadow 8 feet long at the same time and location. How ta

ll is the Flagpole

1 answer:

Kaylis [27]2 years ago

4 0

24 feet
Set up a ratio of object height to shadow length.
So x/32=6/8
8(4)=32 so 6(4) would be 24.

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A researcher studying public opinion of proposed Social Security changes obtains a simple random sample of 35 adult Americans an

Liula [17]

Answer:

Adult required in the case of “a” 28 and in the case of “b” the adult requirement is 19.

Step-by-step explanation:

(a) The percentage of adult that support the change is 20 percent.

Now calculate the number of adult required.

Given p = 0.20

Use the below condition:

$np(1 – p) \geq 10 \\n \times 0.20 (1 – 0.20) = 10 \\n = 63 round off$

Since 35 adults are already there so required adults are 63 -35 = 28

(b) The percentage of adult that support the change is 25 percent.

Now calculate the number of adult required.

Given p = 0.25

Use the below condition:

$np(1 – p) \geq 10 \\n \times 0.25 (1 – 0.25) = 10 \\n = 54 (round off)$

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2 years ago

Carla uses a compass and straightedge to construct perpendicular lines. Daryl uses technology to construct perpendicular lines.

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Answer:

Carla used human accuracy to create perpendicular lines.

-She will grab a pencil and a bond paper

-She will grab the straighthead and the compass.

-She will test with the compass if the straighthead is orientated correctly.

-She will now make a line with the correctly orientated straighthead and pencil.

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Daryl, used technological ease to create perpendicular lines.

-He opens his PC

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Step-by-step explanation:

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2 years ago

1. & 2. In the diagram below, points A, B, and C are collinear. Answer each of the following questions. The figure shown bel

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Answer:

a) $\overline{AB}$ = 8 in

b) When the length of AC = $6\frac{1}{2}$ in. and BC = $3\frac{1}{2}$ in. $\overline{AB}$ = 10 in

c) When the length of AB = 10.2 in. and BC = 3.7 in. $\overline {AC}$ = 6.5 in

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Step-by-step explanation:

a) When the length of AC = 5 in. and CB = 3 in. we have;

The length of $\overline {AB}$ = AC + CB (segment addition postulate)

Therefore;

$\overline{AB}$ = 5 in. + 3 in. = 8 in.

b) When the length of AC = $6\frac{1}{2}$ in. and BC = $3\frac{1}{2}$ in. we have;

The length of $\overline {AB}$ = AC + CB (segment addition postulate)

Therefore;

$\overline{AB}$ = $6\frac{1}{2}$ in.+ $3\frac{1}{2}$ in. = 10 in.

c) When the length of AB = 10.2 in. and BC = 3.7 in. we have;

The length of $\overline {AC}$ = AB - BC (converse of the segment addition postulate)

Therefore;

$\overline {AC}$ = 10.2 in.+ 3.7 in. = 6.5 in.

d) When the length of AB = $4\frac{3}{4}$ in. and BC = $3\frac{1}{4}$ in. in. we have;

The length of $\overline {BC}$ = AB - AC (converse of the segment addition postulate)

Therefore;

$\overline {BC}$ = $4\frac{3}{4}$ in. - $3\frac{1}{4}$ in.= $1\frac{1}{2}$ in.

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2 years ago

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Answer: Sorry mate, but there is nothing to answer.

Step-by-step explanation:

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2 years ago