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3 years ago

How is 4,9 and 4,-9 different

Mathematics

1 answer:

Mkey [24]3 years ago

4 0

Answer:

They are different because they have different signs

Step-by-step explanation:

In 4,9 both values are positive whereas in 4,-9 the 9 is negative and the 4 is positive.

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Stephanie is going to summer camp. There are three cabins to which she could be assigned: pin cabin , maple cabin, or spruce cab

pickupchik [31]

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4 years ago

Subtract-X2 + 9x -- 6 from 4x + 8 plz explain

marta [7]

Answer: -5x+x^(2)+2

Step-by-step explanation: Simplify the expression.

-X2 + 9x -- 6 from 4x + 8

sorry if im wrong

3 0

3 years ago

The student council had a canned food drive. They collected a total of 63 cans on wednesday. This is 21% of the total. How many

Naddik [55]

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3 years ago

What is the modulus and argument after (StartRoot 3 EndRoot) (cosine (StartFraction pi Over 18 EndFraction) + I sine (StartFract

fgiga [73]

Answer:

$|z| = 27$ -- Modulus

$\theta = \frac{\pi}{3}$ --- Argument

Step-by-step explanation:

Given

$((\sqrt 3)(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18}))^6$

Required

Determine the modulus and the argument

We have that:

$z = ((\sqrt 3)(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18}))^6$

Expand:

$z = (\sqrt 3)^6(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6$

$z = 27(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6$

A complex equation can be expressed as:

$z = |z| e^{i\theta}$

Where

$|z| = modulus$

$\theta = argument$

Where

$e^{i\theta} = (cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})$

So:

$z = 27(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6$ becomes

$z = 27(e^{i\frac{\pi}{18}})^6$

By comparison:

$e^{i\theta} = (e^{i\frac{\pi}{18}})^6$

This gives:

${i\theta} = i\frac{\pi}{18}}*6$

${i\theta} = i\frac{6\pi}{18}}$

${i\theta} = i\frac{\pi}{3}}$

Divide through by i

$\theta = \frac{\pi}{3}$

Hence, the modulus, z is:

$|z| = 27$

And the argument $\theta$ is

$\theta = \frac{\pi}{3}$

4 0

3 years ago

Which of the following graphs is described by the function given below? y = x2 - 6x-7

Zanzabum

Answer:

Step-by-step explanation:

We are given the function:

$\displaystyle y = x^2 - 6x - 7$

And we want to determine its graph.

One of the most important features of a quadratic is its vertex. So, we can start by finding the vertex using the formulas:

$\displaystyle \text{Vertex} = \left(-\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right)$

In this case, a = 1, b = -6, and c = -7.

Find the x-coordinate of the vertex:

$\displaystyle x = -\frac{(-6)}{2(1)} = 3$

Substitute this back into the equation to find the y-coordinate:

$\displaystyle y(3) = -16$

Therefore, our vertex is at (3, -16).

The only graph whose quadratic's vertex is at (3, -16) is Graph A. Thus, our answer is A.

5 0

3 years ago