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WITCHER [35]
3 years ago
13

What is the sum of 1/9, 2/3, and 5/18? A. 19/18 B.4/15 C. 12/9 D. 8/20

Mathematics
1 answer:
kari74 [83]3 years ago
8 0

Answer:

19/18

Step-by-step explanation:

The GCF of 9, 3, and 18 is 18.

Each denominator must be multiplied to 18, and as a result what you multiply in the denominator MUST be multiplied in the numerator.

9 * 2 = 18

1 * 2 = 2

2/18

3 * 6 = 18

6 * 2 = 12

12/18

5/18

Add all three fractions together:

12/18 + 5/18 + 2/18 = 19/18

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The ratio of Rogers age to his sons is 7:3. If the sum of their ages are 60 how old is Rogers son
Nimfa-mama [501]

Answer:24

Step-by-step explanation:

Sum of their ages is 60 yr. As such

7x + 3x = 60

10x = 60

x = 60 / 10

x = 6

The rationale is 6, therefore

Father's age is 7x = 7 × 6= 42 years

Son's age is 3x = 3 × 6 = 18 years

Difference in their ages

42 - 18 = 24 years

5 0
3 years ago
Jeannie got a new pair of eye glasses. She was able to pay $15 at the time
Lisa [10]

Answer:

6 months, i used the equation from part a so i know it’s right

Step-by-step explanation:

a) 15 + 12x = 87

b) 12x = 87-15=72

72/12 = 6

3 0
3 years ago
Read 2 more answers
Find the length of side BC. Round your answer to the nearest tenth.
Arturiano [62]

Answer:

2.5

Step-by-step explanation:

(6)cos(65)

7 0
2 years ago
An angle is five times its supplement. Find both angles.
noname [10]
The measure of the smaller angle is 30 degrees.
The measure of the larger angle is 150 degrees.

What I did:
supplementary angle=180 degrees.
<span>An angle is five times its supplement=180/6=
30
30*5=150
150+30=180

</span>
5 0
3 years ago
On the basis of data collected during an experiment, a biologist found that the growth of a fruit fly population (Drosophila) wi
Ket [755]

Answer:

(a). 15

(b). 78

Step-by-step explanation:

Growth of the population of a fruit fly is modeled by

N(t) = \frac{600}{1+39e^{-0.16t} }

where t = number of days from the beginning of the experiment.

(a). For t = 0 [Initial population]

N(0) = \frac{600}{1+39e^{-0.16\times 0} }

       = \frac{600}{1+39}

       = \frac{600}{40}

       = 15

Initial population of the fruit flies were 15.

(b).Population of the fruit fly colony on 11th day.

N(11) = \frac{600}{1+39e^{-0.16\times 11} }

       = \frac{600}{1+39e^{-1.76} }

       = \frac{600}{1+39\times 0.172 }

       = \frac{600}{1+6.71}

       = \frac{600}{7.71}

       = 77.82

       ≈ 78

On 11th day number of fruit flies colony were 78.

3 0
4 years ago
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