Answer:
There could be 0, 2, or 4 complex solutions
Step-by-step explanation:
The Fundamental Theorem of Algebra states that any polynomial with n degree will have n solutions So since the degree of the polynomial you provided has a degree of 4, that means there are 4 possible solutions. This question specifically asks for complex zeroes. Complex zeroes come in conjugate pairs, so that means if you have one complex zero, there is another complex zero which is it's conjugate. For this reason, there can only be an even number of complex zeroes. And since there's 4 possible solutions, There could be 0, 2, or 4 complex solutions
Answer:
s = 2q + 3
Step-by-step explanation:
A linear function has the form:
● y = mx + b
● y is the output of the function
● x is the variabke that we input
● b is the y-intetcept.
Focus on y and x.
Notice that y depends of the value of x. The value of y changes by changing x. So the value of x controls the output y.
y is dependent but x is not.
■■■■■■■■■■■■■■■■■■■■■■■■■■
● 6q = 3s - 9
We want q to be the independent variable wich means that q will be the input. Therefore s should be the output.
The strategy we are going to follow is separating s in one side alone.
● 6q = 3s - 9
Add 9 to both sides
● 6q + 9 = 3s -9 + 9
● 6q + 9 = 3s
Divide both sides by 3
● (6q + 9)/3 = (3s)/3
● (6q)/3 + 9/3 = s
● s = 2q + 3
So the answer is s = 2q + 3
Answer: 32
Step-by-step explanation:
Spencer would be the correct one because it's easier to keep your variables positive when trying to solve. Therefore, in order to keep the variable positive, one would have to add 4x to both sides.
10 weeks
Duane adds $5 every other week so that's 5 weeks out of 10. 5 x 5 = 25
Mick adds $2 every week so,
2 x 10 = 20
25 + 20 = 45
