All categories

3 years ago

What is the following product? 3√10(y^2√4 + √8y)

Mathematics

2 answers:

Elenna [48]3 years ago

8 0

Answer:

6y^2√10 +12y √5

Step-by-step explanation:

3√10(y^2√4 + √8y)

Distribute

3√10(y^2√4) +3√10 (√8y)

3y^2 √40+3y√80

We know that √ab = √a√b

3y^2 √4*√10+3y√16√5

3y^2 *2*√10+3y*4√5

6y^2√10 +12y √5

tatiyna3 years ago

8 0

<h2>Answer:</h2>

<u>The product is</u><u> 18.973666y2+26.832816y</u>

<h2>Step-by-step explanation:</h2>

3√10(y2√4+√8y)

Let's simplify step-by-step.

18.973666y2+26.832816y

As we see

There are no like terms.

The product is =18.973666y2+26.832816y

You might be interested in

I need help with solving 378+16 but it is adding using groups of 10 and 100

hammer [34]

394 is the answer using addition

7 0

3 years ago

John is making trail mix he mixed 10.33 cups of raisins 12.25 cups of pretzels and 7.50 cups of chocolate to make 4 servings est

Mariulka [41]

Answer: 30.1

Step-by-step explanation:

Cups of raisins mixed= 10.33

Cups of pretzels mixed= 12.25

Cups of chocolate mixed= 7.50

When each ingredients is rounded to the nearest tenths, it will be:

Cups of raisins mixed= 10.3

Cups of pretzels mixed= 12.3

Cups of chocolate mixed= 7.5

Total trail mixed by John= 10.3 + 12.3 + 7.5 = 30.1

30.1 cups was mixed together by John.

7 0

4 years ago

Read 2 more answers

Is 3(c-2) and 3x-6 equivalent

seropon [69]

Yes fam they are...........

3 0

3 years ago

Read 2 more answers

Simplify this please

Ugo [173]

Answer:

$\frac{12q^{\frac{7}{3}}}{p^{3}}$

Step-by-step explanation:

Here are some rules you need to simplify this expression:

Distribute exponents: When you raise an exponent to another exponent, you multiply the exponents together. This includes exponents that are fractions. $(a^{x})^{n} = a^{xn}$

Negative exponent rule: When an exponent is negative, you can make it positive by making the base a fraction. When the number is apart of a bigger fraction, you can move it to the other side (top/bottom). $a^{-x} = \frac{1}{a^{x}}$ , and to help with this question: $\frac{a^{-x}b}{1} = \frac{b}{a^{x}}$ .

Multiplying exponents with same base: When exponential numbers have the same base, you can combine them by adding their exponents together. $(a^{x})(a^{y}) = a^{x+y}$

Dividing exponents with same base: When exponential numbers have the same base, you can combine them by subtracting the exponents. $\frac{a^{x}}{a^{y}} = a^{x-y}$

Fractional exponents as a radical: When a number has an exponent that is a fraction, the numerator can remain the exponent, and the denominator becomes the index (example, index here ∛ is 3). $a^{\frac{m}{n}} = \sqrt[n]{a^{m}} = (\sqrt[n]{a})^{m}$

$\frac{(8p^{-6} q^{3})^{2/3}}{(27p^{3}q)^{-1/3}}$ Distribute exponent

$=\frac{8^{(2/3)}p^{(-6*2/3)}q^{(3*2/3)}}{27^{(-1/3)}p^{(3*-1/3)}q^{(-1/3)}}$ Simplify each exponent by multiplying

$=\frac{8^{(2/3)}p^{(-4)}q^{(2)}}{27^{(-1/3)}p^{(-1)}q^{(-1/3)}}$ Negative exponent rule

$=\frac{8^{(2/3)}q^{(2)}27^{(1/3)}p^{(1)}q^{(1/3)}}{p^{(4)}}$ Combine the like terms in the numerator with the base "q"

$=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(2)}q^{(1/3)}}{p^{(4)}}$ Rearranged for you to see the like terms

$=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(2)+(1/3)}}{p^{(4)}}$ Multiplying exponents with same base

$=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(7/3)}}{p^{(4)}}$ 2 + 1/3 = 7/3

$=\frac{\sqrt[3]{8^{2}}\sqrt[3]{27}p\sqrt[3]{q^{7}}}{p^{4}}$ Fractional exponents as radical form

$=\frac{(\sqrt[3]{64})(3)(p)(q^{\frac{7}{3}})}{p^{4}}$ Simplified cubes. Wrote brackets to lessen confusion. Notice the radical of a variable can't be simplified.