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Pavel [41]
2 years ago
12

The figure below shows a quadrilateral ABCD. Sides AB and DC are congruent and parallel:

Mathematics
1 answer:
kirza4 [7]2 years ago
4 0

The statement that best describes a flaw in the students' proof is;

Option D; Angle DBC and angle BDA form a pair of corresponding angles, not a pair of alternate interior angles, which are congruent.

From the given image, we can see that;

AB ≅ DC

Let us analyze each given option;

A) ∠DBC and ∠BDA are in the same triangle ΔBDC. Now, they can't be a pair of vertical angles because vertical angles are a pair of opposite angles formed when two lines intersect but this is not the case here.

They are also not alternate interior angles because alternate angles are formed when a transverse line intersects two coplanar lines and again that is not the case here.

B) In ΔABD and ΔBDC, we see that;

AB = DC. Also, by theorem of alternate interior angles, we can tell that;

∠ABD = ∠BDC

Similarly, ∠BDA = ∠DBC from alternate interior angles.

Thus, there is one corresponding side and two non-included angles which means the triangles are congruent by AAS Congruency postulate.

C) As seen in B above, this statement is correct because the triangles are congruent by AAS postulate.

D) Corresponding angles lie on the same side of the transversal.  In this case, ∠BDA and ∠DBC lie on opposite sides and are even congruent by alternate interior angles.

Read more about congruency at; brainly.com/question/7727792

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