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Pavel [41]
3 years ago
12

The figure below shows a quadrilateral ABCD. Sides AB and DC are congruent and parallel:

Mathematics
1 answer:
kirza4 [7]3 years ago
4 0

The statement that best describes a flaw in the students' proof is;

Option D; Angle DBC and angle BDA form a pair of corresponding angles, not a pair of alternate interior angles, which are congruent.

From the given image, we can see that;

AB ≅ DC

Let us analyze each given option;

A) ∠DBC and ∠BDA are in the same triangle ΔBDC. Now, they can't be a pair of vertical angles because vertical angles are a pair of opposite angles formed when two lines intersect but this is not the case here.

They are also not alternate interior angles because alternate angles are formed when a transverse line intersects two coplanar lines and again that is not the case here.

B) In ΔABD and ΔBDC, we see that;

AB = DC. Also, by theorem of alternate interior angles, we can tell that;

∠ABD = ∠BDC

Similarly, ∠BDA = ∠DBC from alternate interior angles.

Thus, there is one corresponding side and two non-included angles which means the triangles are congruent by AAS Congruency postulate.

C) As seen in B above, this statement is correct because the triangles are congruent by AAS postulate.

D) Corresponding angles lie on the same side of the transversal.  In this case, ∠BDA and ∠DBC lie on opposite sides and are even congruent by alternate interior angles.

Read more about congruency at; brainly.com/question/7727792

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Step-by-step explanation:

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The area is the product of two linear dimensions, so its scale factor is the product of the linear dimension scale factors. That is, the scale factor for area is the square of the linear dimension scale factor.

Similarly, volume is the product of three linear dimensions, so its scale factor is the cube of the linear dimension scale factor.

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Step-by-step explanation:

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Step-by-step explanation:

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