Question

The length of a rectangle is 3 more inches than the width. Find the length and width of the rectangle is the perimeter of the rectangle is 54 inches.
#7 Write an equation that represents the situation. Explain any variable used.




#8 Solve the equation. Show your work. State your solution as a complete sentence

Answer 1

Part A:

Let the width of the rectangle be = x inches

As given, the length of a rectangle is 3 more inches than the width so let the length of the rectangle be = x+3 inches

Perimeter is given as = 54 inches

Perimeter = $2(l+b)$

Equation becomes:

$2(x+3+x)$=54

$2(2x+3)=54$

Part B:

Solving the equation we get

$4x+6=54$

$4x=54-6$

$4x=48$

$x=12$

Hence, the width of the rectangle is 12 inches

Length = x+3 = 12+3 = 15 inches

Hence, length of the rectangle is 15 inches.