What is the point-slope form of a line with slope -3 that contains the point
(10, -1)?
       
      
                
     
    
    
    
    
    1 answer:
            
              
              
                
                
Answer:
y - (-1) = -3(x-10)
y+1= -3x+30
y= -3x+30-1
y= -3x+29
 
                                
             
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X/3=1351/7
cross multiply
7x=4053
divide by seven on both sides
x=579