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ruslelena [56]
3 years ago
13

One day, Alonso decided to keep a record of the time he spent walking and the distance he walked. Which of the following are tru

e about the data shown? Check all that apply.
A 2-column table with 4 rows. Column 1 is labeled Time (hours) with entries 0, 1, 2, 3. Column 2 is labeled Distance (miles) with entries 1, 4, 7, 10.

The points would lie on a straight line that passes through the origin, so the relationship is proportional.
The points would not lie on a straight line, so the relationship is not proportional.
The points would lie on a straight line that does not pass through the origin, so the relationship is not proportional.
The equation y = 4x represents the data.
The equation y = 4x does not represent the data
Mathematics
2 answers:
wel3 years ago
9 0

Answer:

The answer is C and E

Step-by-step explanation:

Vladimir [108]3 years ago
6 0

Answer:

C and E

Step-by-step explanation:

Just did it.

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Solve using the substitution method. Show steps please.
rusak2 [61]

Answer:

X=1, Y=4

Step-by-step explanation:

IN THE ATTACHED FILE

7 0
3 years ago
Fill in the blank. Give O below, you can conclude that DF is congruent to _____.
lakkis [162]

Answer:

B. BC

Step-by-step explanation:

4 0
3 years ago
The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 5 m
Grace [21]

Answer:

0.35

Step-by-step explanation:

we know that

The formula to use for uniform distribution is equal to

P( X < x) = \frac{x-a}{b-a}

where,

b is the upper limit of the distribution which is 5 minutes in this case.

a is the lower limit of the distribution which is 0 minutes in this case.

x is the concerned value which is 1.75 minutes in this case.

substitute the given values

P( X< 1.75) = \frac{1.75-0}{5-0}=0.35

That means

The probability that a randomly selected passenger has a waiting time less than 1.75 minutes is 0.35

5 0
3 years ago
How do I solve 2m + n = 2 and 3m - 2n = 3 using substitution?
Leona [35]

\huge \boxed{\mathbb{QUESTION} \downarrow}

  • Solve 2m + n = 2 and 3m - 2n = 3 using substitution.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

We can use the substitution method to solve linear equations of this form. Let's solve for m & n.

\left. \begin{array}  { l  }  { 2 m + n = 2 } \\ { 3 m - 2 n = 3 } \end{array} \right.

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

2m+n=2, \: 3m-2n=3

Choose one of the equations and solve it for m by isolating m on the left-hand side of the equal sign.

2m+n=2

Subtract n from both sides of the equation.

2m=-n+2

Divide both sides by 2.

m=\frac{1}{2}\left(-n+2\right)  \\

Multiply 1/2 times -n+2.

m=-\frac{1}{2}n+1  \\

Substitute -\frac{n}{2}+1\\ for m in the other equation, 3m-2n=3.

3\left(-\frac{1}{2}n+1\right)-2n=3  \\

Multiply 3 times -\frac{n}{2}+1\\.

-\frac{3}{2}n+3-2n=3  \\

Add -\frac{3n}{2}\\ to -2n.

-\frac{7}{2}n+3=3  \\

Subtract 3 from both sides of the equation.

-\frac{7}{2}n=0  \\

Divide both sides of the equation by -\frac{7}{2}\\, which is the same as multiplying both sides by the reciprocal of the fraction.

\large \underline{\underline{ \bf \: n=0 }}

Substitute 0 for n in m=-\frac{1}{2}n+1\\. Because the resulting equation contains only one variable, you can solve for m directly.

\large \underline{ \underline{\bf \: m=1 }}

The system is now solved.

\huge \boxed{ \boxed{ \bf \: m=1, \: n=0 }}

4 0
3 years ago
if any one can help me that would be awesome 1. − 8 = 5 b − 3 b 2. k − 8 + 6 k = 20 3. 723. 4. 6 ( 3 + 3 x ) = 72 364. 5 ( m + 4
Morgarella [4.7K]

Answer:

1)b=-4

2)k=4

3)can u explain what #3 and 4 say

4)?

5)0/ no solution

Step-by-step explanation:

5 0
3 years ago
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