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3 years ago

I have to repost this because the first time I was not giving correct answers.

Mathematics

1 answer:

SSSSS [86.1K]3 years ago

8 0

Answer and Step-by-step explanation:

We are given: 18x - 2(3x + 1) = 5x - 16

First, lets distribute the -2 to the 3x and 1.

18x - 6x - 2 = 5x - 16

Now, we combine like terms.

12x - 2 = 5x - 16

Next, we add 2 to each side.

12x = 5x -14

Now, we subtract 5x from both sides.

7x = -14

Finally, we divide by 7 on both sides.

x = -2

Statements: Reasons:

18x - 2(3x + 1) = 5x - 16 Given

18x - 6x - 2 = 5x - 16 Distributive Property of Equality

12x - 2 = 5x - 16 Combine like terms

12x = 5x -14 Addition Property of Equality

7x = -14 Subtraction Property of Equality

x = -2 Division Property of Equality

#teamtrees #WAP (Water And Plant)

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1. Storing milk at temperatures colder than 35°F can affect its quality of taste. However, storing milk at temperatures warmer t

Mazyrski [523]

Answer:

Part (A): The required inequality is T < 35 or t >40.

Part (B): The correct option is C) Only x=7.

Part (C) |x+1|+5=2 has no solution; |4x+12|=0 has one solution; |3x|=9 has two solution.

Step-by-step explanation:

Consider the provided information.

Part (A)

Storing milk at temperatures colder than 35°F can affect its quality of taste. However, storing milk at temperatures warmer than 40°F is an unsafe food practice.

The union is written as A∪B or “A or B”.

The intersection of two sets is written as A∩B or “A and B”

We need to determine the inequalities represent the union of these improper storage.

That means we will use A∪B or “A or B”.

The improper storage temperatures is when temperature is less than 35°F or greater than 40°F.

Hence, the required inequality is T < 35 or t >40.

Part (B) 15| x-7|+4=10|x-7|+4

Solve the inequality as shown below:

Subtract 4 from both sides.

$15| x-7|+4-4=10|x-7|+4-4$

Subtract 10|x-7| from both sides

$5\left|x-7\right|=0\\\left|x-7\right|=0\\x=7$

Hence, the correct option is C) Only x=7.

Part (C) Match the solution,

$\left|x+1\right|+5=2$

Subtract 2 from both sides.

$\left|x+1\right|=-3$

Absolute value cannot be less than 0.

Hence, |x+1|+5=2 has no solution.

$|4x+12|=0$

$4x+12=0$

$x=-3$

Hence, |4x+12|=0 has one solution.

$|3x|=9$

$\mathrm{If}\:|u|\:=\:a,\:a>0\:\mathrm{then}\:u\:=\:a\:\quad \mathrm{or}\quad \:u\:=\:-a$

$3x=-9\quad \mathrm{or}\quad \:3x=9\\x=-3\quad \mathrm{or}\quad \:x=3$

Hence, |3x|=9 has two solution.

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Answer:

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