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4 years ago

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For each handmade card Jacquie sells, she makes a profit of $0.35. In one week she made a profit of $42. she sells the cards for

$0.75 Part 1 : about how many greeting cards do she sell that week? Part 2 : about how much did she earn before paying expenses?

1 answer:

NARA [144]4 years ago

5 0

Ella hizo 120 tarjetas al venderlas hizo $90 y menos lel beneficio son $48

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HI MATHS EXPERTS PLS ANSWER ASAP PLS I AM DESPERATE

katovenus [111]

c. 2310 (1st pic)

circumference of circle = 2πr

44= 2 × 22/7 r

44 × 7 / (2 × 22) = r

7 = r

volume of cylinder = πr^2h

= 22/7 × (7)^2 ×15

= 2310

b. -2/x+3 (2nd pic)

(work attached)

a. 80° (3rd pic)

Total number of degrees is 180

180-(60+40)=80

c. 9 (5th pic)

(27^1/3)^2

3^2

=9

sorry i couldn't solve the 4th pic but I hope this helps!

please mark me brainliest!

3 0

3 years ago

According to a research center, 16% of all merchandise sold in a particular country gets returned. A department store in a certa

Mamont248 [21]

Answer:

a) point estimate of the proportion of items returned for the population of sales transactions at the store in the given city

Point estimate = 0.3

b) The 95% confidence interval for the proportion of returns at the store in the given city

( 0.19958,0.40042)

Step-by-step explanation:

Given the Population proportion 'P'= 16% = 0.16

Given data a department store in a certain city sampled 80 items sold in January and found that 24 of the items were returned

The sample proportion $p = \frac{x}{n}$

here x =24 and n = 80

The sample proportion $p = \frac{x}{n} = \frac{24}{80} = 0.3$

a)<u> Point estimate</u>:-

A point estimate of the true proportion P

Point estimate = $p = \frac{x}{n}$

point estimate of the proportion of items returned for the population of sales transactions at the store in the given city

$p = \frac{x}{n} = \frac{24}{80} = 0.3$

b) <u>The 95% confidence interval for the proportion </u>

The 95% confidence interval for the proportion of returns at the store in the given city

$(p - z_{\alpha } \sqrt{\frac{p(1-p)}{n} } , p + z_{\alpha }\sqrt{\frac{p(1-p)}{n} } )$

substitute all values we get ,

$(0.3 - 1.96 \sqrt{\frac{0.3(1-0.3)}{80} } , 0.3 + 1.96\sqrt{\frac{0.3(1-0.3)}{80} } )$

on simplification, we get

(0.3-0.10042 ,0.3+0.10042)

( 0.19958,0.40042)

<u>Conclusion</u>:-

a) point estimate of the proportion of items returned for the population of sales transactions at the store in the given city

Point estimate = 0.3

b) The 95% confidence interval for the proportion of returns at the store in the given city

( 0.19958,0.40042)

5 0

4 years ago

FIND X PLS HELP MEE plss

lorasvet [3.4K]

I’m not sure
But
It could be 26!

6 0

2 years ago

last month, a bookstore ran the following at and sold 85 calculators, generating $4,083 in sales. How many of each type of calcu

Scilla [17]

Answer:

31 scientific calculators

54 graphing calculators

Step-by-step explanation:

X = number of $15 calculators

Y = number of $67 calculators

X+Y = 85 then X = 85-Y

15X+67Y = 4083

substitute for X

15(85-Y)+67Y = 4083

1275 - 15Y + 67Y = 4083

reduce

52Y = 2808

Y = 54

X = 31

6 0

3 years ago

Help meeeeeeee please

Len [333]

Answer:

x=-20

Step-by-step explanation:

x-3/4x=3/10x-1

20x-15x=6x+20

5x=6x+20

5x-6x=20

-x=20

x=-20

6 0

3 years ago