Answer:
step 3: he should have divided both sides by -7
Answer:
The relationship is proportional ✧
The answer is Transitive Property of Angle Congruence
Step-by-step explanation:
1. All the trigonometric values can be found using the unit circle. See attached table.
2. Graph:
desmos.com/calculator/10n7yrm3tm
3. All trig functions are periodic functions. The period of secant and cosecant is 2π. The period of cotangent is π.
4. Using the table from step 1 and the graph from step 2, secant has a domain of x ≠ pi/2, 3pi/2 and a range of x ≤ -1, x ≥ 1. Cotangent has a domain of x ≠ 0, pi, 2pi and a range of -∞ < x < ∞.
5. Graph:
desmos.com/calculator/tldiqt7qra
Cosecant has the same graph as secant shifted π/2 to the right. So they have different domains, but the same range.
Answer:
5 5/11 hours
Step-by-step explanation:
So, there is a trick to doing this.
You would first need to get their work rate into the same measurements.
That's why we will find out how much they each work in one hour.
Tommy does 1/12 of the work in one hour while Robert does 1/10.
Here we can add them both up to make 11/60.
They finish 11/60 of the work in one hour.
They finish the job in 5 5/11 hours.