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4 years ago

10

Need help please hurry DON'T TYPE AND ACT LIKE YOUR GONNA ANSWER THE QUESTION IF YOUR NOT GOING TO who ever gets it right i will

give you the brainiest!
good luck!

1 answer:

borishaifa [10]4 years ago

3 0

-4 is the y intercept, then go down -5/6 and then right 1.

Hopefully it helps and that's right haha

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4 years ago

Read 2 more answers

What is the equation in standard form of a parabola that models the values in the table

shusha [124]

Answer:

Y=4x^2-3x+5

Step-by-step explanation:

For the standard form equation to model the values in the table, each value of x in the table should give the matching the y value when substituted into the equation. We will test each equation:

<u> $Y=-4x^2+3x+5$ for (-1,12)</u>

$Y=-4(-1)^2+3(-1)+5=-4(1)+-3+5=-4+-3+5=-2\\$

This does not give 12 as the answer and is not a solution.

<u> $Y=-4x^2-3x+5$ for (-1,12)</u>

$Y=-4(-1)^2-3(-1)+5=-4(1)+3+5=-4+3+5=4\\$

This does not give 12 as the answer and is not a solution.

<u> $Y=3x^2-4x+5$ for (-1,12)</u>

$Y=3(-1)^2-4(-1)+5=3(1)+4+5=3+4+5=12\\$

This does give 12 as the answer and is a possible solution.

We now try (2,15).

$Y=3(2)^2-4(2)+5=3(4)-8+5=12-8+5=9\\$

This does not give 15 as the answer and is not a possible solution.

<u> $Y=4x^2-3x+5$ for (-1,12)</u>

$Y=4(-1)^2-3(-1)+5=4(1)+3+5=4+3+5=12\\$

This does not give 12 as the answer and is not a solution.

We now try (2,15).

$Y=4(2)^2-3(2)+5=4(4)-6+5=16-6+5=15\\$

This does give 15 as the answer and is a solution.

This is the standard form of the equation.

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