3 years ago

Integral of ln times cube root x dx

1 answer:

3 0

If u = ln(x^(1/3))
then by the chain rule
du = [1/x^(1/3)] * (1/3)x^(-2/3) dx = (1/3)(1/x) dx.
You could get there faster by noting that
ln(x^(1/3)) = (1/3) ln(x), so du = (1/3) dx/x

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