All categories

2 years ago

Could someone explain this to me. I don’t get it

Mathematics

1 answer:

Sergeeva-Olga [200]2 years ago

6 0

What grade are y in I can maybe help

You might be interested in

Please help me with 9 I really need it

MissTica

Answer:

605 boys

Step-by-step explanation:

If the ratio of boys to girls is 5:7

and there are 847 girls

we can plug this value into the ratio by doing something like:

5:7

= 5/7

= x/847

Because the ratio has to be the same, we can substitute x for the number of boys and solve by the cross method or whatever you guys call it.

5 x

--- x ------

7 847

The x in the middle is just to show the direction you are multiplying.

the 5 is multiplied by the 847 and the 7 is multiplied by x.

847 * 5 = 4,235

4,235 divided by 7 is 605

605 is your answer.

The cross method can be used in most situations.

* is used to represent multiplication btw

4 0

2 years ago

Jill’s coach used a computer program to help her improve the distance she can throw a softball. The computer gave a readout of t

Jlenok [28]

Answer:

11.08 feet

Step-by-step explanation: I just got it wrong and it told me the answer. :/

5 0

2 years ago

Read 2 more answers

Amy drove her car 241 miles. The car used 8.07 gallons of gasoline on the drive. Estimate the cars gasoline mileage in miles per

Ket [755]

Miles driven in 8.07 gallons = 241 miles
Miles driven in 1 gallons = (241/8.07) * 1
= 29.86 miles

5 0

2 years ago

Which of the following relations is a function?

ale4655 [162]

Answer:

{(5, –4), (–4, 5), (–5, 4), (4, –5)}

5 0

3 years ago

Read 2 more answers

A certain restaurant always overbooks. If possible. At 7:00 pm the restaurant can seat 50 parties, but takes reservations for 53

oee [108]

Answer:

The probability that the restaurant can accommodate all the customers who do show up is 0.3564.

Step-by-step explanation:

The information provided are:

At 7:00 pm the restaurant can seat 50 parties, but takes reservations for 53.
If the probability of a party not showing up is 0.04.
Assuming independence.

Let X denote the number of parties that showed up.

The random variable X follows a Binomial distribution with parameters n = 53 and p = 0.96.

As there are only 50 sets available, the restaurant can accommodate all the customers who do show up if and only if 50 or less customers showed up.

Compute the probability that the restaurant can accommodate all the customers who do show up as follows:

$P(X\leq 50)=1-P(X>50)\\=1-P(X=51)-P(X=52)-P(X=53)\\=1-[{53\choose 51}(0.96)^{51}(0.04)^{53-51}]-[{53\choose 52}(0.96)^{52}(0.04)^{53-52}]\\-[{53\choose 53}(0.96)^{53}(0.04)^{53-53}]\\=1-0.27492-0.25377-0.11491\\=0.3564$

Thus, the probability that the restaurant can accommodate all the customers who do show up is 0.3564.

7 0

3 years ago