Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.
Step-by-step explanation:
Since we have given that
Integers between 10000 and 99999 = 99999-10000+1=90000
n( divisible by 3) = 
n( divisible by 5) = 
n( divisible by 7) = 
n( divisible by 3 and 5) = n(3∩5)=
n( divisible by 5 and 7) = n(5∩7) = 
n( divisible by 3 and 7) = n(3∩7) = 
n( divisible by 3,5 and 7) = n(3∩5∩7) = 
As we know the formula,
n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.
Answer:
Step-by-step explanation:
2/12 I think it's beenalong time sinces have done this
The first digit can be any one of the numbers 2-9 That a total of 8 numbers.
The next 6 digits can be any permutation of 6 from the numbers 0 to 9.
(10 numbers)
nPr = n! / r!
so here we have 10P6 = 10! / 6! = 10*9*8*7 = 5040
So final answer is 8 * 5040 = 40,320
Answer:
3(238+12) is the expression
Step-by-step explanation:
hope this helps
X=22
Area is found by multiplying (x+7)and (2x-1) together. 22+7=29, 2(22) -1 = 43, 43+29=72